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Wireless Network Design: Optimization Models and Solution ...

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180 Syam Menon<br />

✤✜<br />

✇ ✇<br />

e<br />

d<br />

⑦MTSO c ✇<br />

a<br />

b<br />

❞ ✇ ✇<br />

u<br />

❞<br />

✬✩ w<br />

✬✩<br />

✣✢<br />

� ❅<br />

❞ ✲<br />

��✠ ❅❘ ✛ ❞<br />

v<br />

❅❍❨ ❍ x<br />

❍<br />

✫✪<br />

❅❅❅❅<br />

❍✫✪<br />

❍<br />

❍<br />

❍ ✬✩<br />

❍<br />

❍ y<br />

� ❄✛<br />

❍ ❞<br />

❅ ✟<br />

✟<br />

✻<br />

✻❅❅❅❅<br />

✟<br />

✟ ✫✪<br />

✬✩<br />

✟<br />

✟<br />

✗✔<br />

✟<br />

✟<br />

✲<br />

✛✟✙<br />

✟ z ❞<br />

✖✕<br />

✫✪<br />

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Fig. 8.1 Example <strong>Network</strong><br />

min ∑ i∈V<br />

(P1) ∑ i∈V<br />

∑ ci jxi j<br />

j∈R<br />

st ∑ xi j = Si ∀i ∈ V (8.1)<br />

j∈R<br />

∑<br />

j∈H<br />

Di<br />

Si<br />

xi j ≤ 2K (8.2)<br />

xi j ∈ {0, 1} ∀i ∈ V, ∀ j ∈ R (8.3)<br />

The objective function minimizes the total cost of connecting cells to nodes on the<br />

ring. Constraint set 8.1 ensures that the diversity requirement of every cell is met,<br />

while constraint 8.2 ensures that the ring capacity is not exceeded. All cell dem<strong>and</strong>s<br />

will ultimately terminate at the MTSO, <strong>and</strong> therefore these flows must enter the<br />

MTSO in either the clockwise or the counter-clockwise direction. Consequently, the<br />

total traffic in the ring cannot exceed 2K when the ring capacity is K. Note that if<br />

traffic is allowed to flow just in one direction, the only alteration to the formulation<br />

would be to limit the total traffic on the ring to K. As already mentioned, Dutta<br />

<strong>and</strong> Kubat [4] solve problem (P1) via a heuristic technique based on Lagrangian<br />

relaxation.<br />

8.2.2 Reduction to a Binary Knapsack Problem<br />

Formulation (P1) involves |V | × |R| variables <strong>and</strong> |V | + 1 constraints. In this section,<br />

we show how (P1) can be reduced to a significantly smaller binary knapsack<br />

problem (with at most |V | variables). This is convenient, as the size of the binary<br />

knapsack problem to be solved is independent of the values of |H| <strong>and</strong> Si. A variety<br />

of specialized solution approaches are available to solve the binary knapsack prob-

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