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Wireless Network Design: Optimization Models and Solution ...

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186 Syam Menon<br />

−λ1di1 −λ2di2 −λT di j<br />

✓✏ ✓✏ ✓✏<br />

H1 H2 H j<br />

✒✑ ✒✑ ✒✑<br />

✓✏ � ✓✏<br />

�����✒<br />

hi1 h ✲<br />

i j ✲<br />

❆ ❆ ✁✕ ❅<br />

❆❆❆❆❆❆❆❆❆❆❆❯<br />

❅❅❅❅❘<br />

❅❅❅❅❘<br />

❆ ✁<br />

❆ ✁<br />

connection to<br />

HUB<br />

P<br />

connection to<br />

MTSO<br />

(h i1 + s i1 )<br />

r i1<br />

(r i2 +t i2 )<br />

✒✑<br />

✒✑<br />

❅<br />

❅❅❅<br />

❅❘ ✓✏ ✁ ✓✏ ✓✏<br />

r<br />

R<br />

i2<br />

1 ✲ R2 R j<br />

✒✑ ✒✑ ✒✑<br />

✁✁✁✁✁✁✁✁✁✁✁✕<br />

✁ ❆<br />

✁ ❆<br />

✁ ❆❯ � ri j ✲<br />

�����✒<br />

(h i2 + s i2 )<br />

Fig. 8.2 Representing the Subproblem<br />

(r i j +t i j ) � ���� � ✒<br />

problem, since we have a graph without cycles <strong>and</strong> since every period has to be<br />

visited exactly once, we can add the node weights to the weights on the edges entering<br />

the nodes Hj without loss of generality. Note that this problem can also be<br />

represented as a min-cost-flow problem where one unit of flow needs to be sent from<br />

P to Q. In our context, the min-cost-flow formulation (without the node weights) is<br />

(S1) below.<br />

min ∑<br />

(i, k)∈E<br />

cikzik<br />

s.t. zPR + zPH 1 1 = 1 (8.17)<br />

zPR1 − zR1R2 − zR1H2 = 0 (8.18)<br />

zPH − zH 1 1R − zH 2 1H2 = 0 (8.19)<br />

zR ( j−1) R j + zH ( j−1) R j − zR jR − zR ( j+1) jH ( j+1) = 0 j = 2,...,(T − 1)(8.20)<br />

(S1) zR ( j−1) Hj + zH ( j−1) H j − zHjR − zHjH = 0 j = 2,...,(T − 1)(8.21)<br />

( j+1) ( j+1)<br />

zR (T −1) RT + zH (T −1) RT − zRT Q = 0 (8.22)<br />

zR (T −1) HT + zH (T −1) HT − zHT Q = 0 (8.23)<br />

zRT Q + zHT Q = 1 (8.24)<br />

zik ∈ {0, 1}∀(i,k) ∈ E (8.25)<br />

The cik are the costs on the edges as identified earlier; E is the set of edges in the<br />

network; zik is a variable indicating flow between nodes i <strong>and</strong> k. Constraint 8.17<br />

indicates flow out of P; constraints 8.18 <strong>and</strong> 8.19 are flow balance constraints on<br />

(h i j + s i j )<br />

0<br />

0<br />

Q

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