28.08.2015 Views

and Cosmology

Extragalactic Astronomy and Cosmology: An Introduction

Extragalactic Astronomy and Cosmology: An Introduction

SHOW MORE
SHOW LESS
  • No tags were found...

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

2. The Milky Way as a Galaxy<br />

68<br />

face brightness (or specific intensity) is preserved. The<br />

flux of a source is given as the product of surface brightness<br />

<strong>and</strong> solid angle. Since the former of the two factors<br />

is unchanged by light deflection, but the solid angle<br />

changes, the observed flux of the source is modified. If<br />

S 0 is the flux of the unlensed source <strong>and</strong> S the flux of<br />

an image of the source, then<br />

μ := S S 0<br />

= ω ω s<br />

(2.82)<br />

describes the change in flux that is caused by a magnification<br />

(or a diminution) of the image of a source. Obviously,<br />

the magnification is a purely geometrical effect.<br />

Magnification for “Small” Sources. For sources <strong>and</strong><br />

images that are much smaller than the characteristic<br />

scale of the lens, the magnification μ is given by the<br />

differential area distortion of the lens mapping (2.77),<br />

( )∣ μ =<br />

∂β ∣∣∣<br />

−1<br />

( )∣<br />

∣ det ≡<br />

∂θ ∣ det ∂βi ∣∣∣<br />

−1<br />

∂θ j<br />

. (2.83)<br />

have magnification either larger or less than unity, depending<br />

on y. The magnification of the two images is<br />

illustrated in Fig. 2.24, while Fig. 2.25 shows the magnification<br />

for several different source positions y. For<br />

y ≫ 1, one has μ + 1<strong>and</strong>μ − ∼ 0, from which we<br />

draw the following conclusion: if the source <strong>and</strong> lens<br />

are not sufficiently well aligned, the secondary image is<br />

strongly demagnified <strong>and</strong> the primary image has magnification<br />

very close to unity. For this reason, situations<br />

with y ≫ 1 are of little relevance since then essentially<br />

only one image is observed which has about the same<br />

flux as the unlensed source.<br />

For y → 0, the two magnifications diverge,<br />

μ ± →∞. The reason for this is purely geometric: in<br />

this case, out of a zero-dimensional point source a onedimensional<br />

image, the Einstein ring, is formed. This<br />

divergence is not physical, of course, since infinite magnifications<br />

do not occur in reality. The magnifications<br />

remain finite even for y = 0, for two reasons. First, real<br />

sources have a finite extent, <strong>and</strong> for these the magnifi-<br />

Hence for small sources, the ratio of solid angles of the<br />

lensed image <strong>and</strong> the unlensed source is described by<br />

the determinant of the local Jacobi matrix. 11<br />

The magnification can therefore be calculated for<br />

each individual image of the source, <strong>and</strong> the total magnification<br />

of a source, given by the ratio of the sum of<br />

the fluxes of the individual images <strong>and</strong> the flux of the<br />

unlensed source, is the sum of the magnifications for<br />

the individual images.<br />

Magnification for the Point-Mass Lens. For a pointmass<br />

lens, the magnifications for the two images (2.81)<br />

are<br />

μ ± = 1 4<br />

(<br />

√<br />

y<br />

√<br />

y2 + 4 + y2 + 4<br />

± 2<br />

y<br />

)<br />

. (2.84)<br />

From this it follows that for the “+”-image μ + > 1for<br />

all source positions y =|y|, whereas the “−”-image can<br />

11 The determinant in (2.83) is a generalization of the derivative in one<br />

spatial dimension to higher dimensional mappings. Consider a scalar<br />

mapping y = y(x); through this mapping, a “small” interval Δx is<br />

mapped onto a small interval Δy, whereΔy ≈ (dy/dx) Δx. The<br />

Jacobian determinant occurring in (2.83) generalizes this result for<br />

a two-dimensional mapping from the lens plane to the source plane.<br />

Fig. 2.24. Illustration of the lens mapping by a point mass M.<br />

The unlensed source S <strong>and</strong> the two images I 1 <strong>and</strong> I 2 of the<br />

lensed source are shown. We see that the two images have<br />

a solid angle different from the unlensed source, <strong>and</strong> they also<br />

have a different shape. The dashed circle shows the Einstein<br />

radius of the lens

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!