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Extragalactic Astronomy and Cosmology: An Introduction

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4. <strong>Cosmology</strong> I: Homogeneous Isotropic World Models<br />

164<br />

than baryons, a sufficient number of highly energetic<br />

photons, with E γ ≥ E b , exist in the Wien tail of the<br />

Planck distribution to instantly destroy newly formed D<br />

by photo-dissociation. Only when the temperature has<br />

decreased considerably, k B T ≪ E b , can the deuterium<br />

abundance become appreciable. With the corresponding<br />

balance equations we can calculate that the formation<br />

rate exceeds the photo-dissociation rate of deuterium at<br />

about T D ≈ 8 × 10 8 K, corresponding to t ∼ 3min.Up<br />

to then, a fraction of the neutrons has thus decayed,<br />

yielding a neutron–proton ratio at T D of n n /n p ≈ 1/7.<br />

After that time, everything happens very rapidly. Owing<br />

to the strong interaction, virtually all neutrons first<br />

become bound in D. Once the deuterium density has<br />

become appreciable, helium (He 4 ) forms, which is a nucleus<br />

with high binding energy (∼ 28 MeV) which can<br />

therefore not be destroyed by photo-dissociation. Except<br />

for a small (but, as we will later see, very important)<br />

remaining fraction, all deuterium is quickly transformed<br />

into He 4 . For this reason, the dependence of helium formation<br />

on the small binding energy of D is known as<br />

the “bottleneck of nucleosynthesis”.<br />

Helium Abundance. The number density of helium nuclei<br />

can now be calculated since virtually all neutrons<br />

present are bound in He 4 . First, n He = n n /2, since every<br />

helium nucleus contains two neutrons. Second, the<br />

number density of protons after the formation of helium<br />

is n H = n p − n n , since He 4 contains an equal number of<br />

protons <strong>and</strong> neutrons. From this, the mass fraction Y of<br />

He 4 of the baryon density follows,<br />

Y =<br />

4n He<br />

=<br />

2n n<br />

= 2(n n/n p )<br />

4n He + n H n p + n n 1 + (n n /n p ) ≈ 0.25 ,<br />

(4.61)<br />

where in the last step we used the above ratio of<br />

n n /n p ≈ 1/7 atT D . This consideration thus leads to<br />

the following:<br />

About 1/4 of the baryonic mass in the Universe<br />

should be in the form of He 4 . This is a robust prediction<br />

of Big Bang models, <strong>and</strong> it is in excellent<br />

agreement with observations.<br />

Fig. 4.13. The evolution of abundances of the light elements<br />

formed in BBN, as a function of temperature (lower axis) <strong>and</strong><br />

cosmic time t (upper axis). The decrease in neutron abundance<br />

in the first ∼ 3 min is due to neutron decay. The density of<br />

deuterium increases steeply – linked to the steep decrease<br />

in neutron density – <strong>and</strong> reaches a maximum at t ∼ 3 min<br />

because then its density becomes sufficiently large for efficient<br />

formation of He 4 to set in. Only a few deuterium nuclei do<br />

not find a reaction partner <strong>and</strong> remain, with a mass fraction of<br />

∼ 10 −5 . Only a few other light nuclei are formed in the Big<br />

Bang, mainly He 3 <strong>and</strong> Li 7<br />

The helium content in the Universe may change later<br />

by nuclear fusion in stars, which also forms heavier<br />

nuclei (“metals”). Observations of fairly unprocessed<br />

material (i.e., that which has a low metal content) reveal<br />

thatinfactY ≈ 0.25. Figure 4.13 shows the result of<br />

a quantitative model of BBN where the mass fraction<br />

of several species is plotted as a function of time or<br />

temperature, respectively.<br />

Dependence of the Primordial Abundances on the<br />

Baryon Density. At the end of the first 3 min, the composition<br />

of the baryonic component of the Universe is<br />

about as follows: 25% of the baryonic mass is bound in<br />

helium nuclei, 75% in hydrogen nuclei (i.e., protons),<br />

with traces of D, He 3 <strong>and</strong> Li 7 . Heavier nuclei cannot<br />

form because no stable nucleus of mass number 5 or<br />

8 exists <strong>and</strong> thus no new, stable nuclei can be formed<br />

in collisions of two helium nuclei or of a proton with<br />

a helium nucleus. Collisions between three nuclei are<br />

far too rare to contribute to nucleosynthesis. The den-

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