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Final NB 2016-2017 Turley

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Theoretical and Actual Yields<br />

Key Terms<br />

<br />

<br />

<br />

(Excess reagent, limiting reagent)<br />

Theoretical and actual yields<br />

Percentage or actual yield<br />

Skills to Develop<br />

Use stoichiometric calculation to determine excess and limiting reagents in a chemical reaction<br />

<br />

<br />

and explain why.<br />

Calculate theoretical yields of products formed in reactions that involve limiting reagents.<br />

Evaluate percentage or actual yields from known amounts of reactants<br />

Theoretical and Actual Yields<br />

Reactants not completely used up are called excess reagents, and the reactant that completely<br />

reacts is called the limiting reagent. This concept has been illustrated for the reaction:<br />

2Na+Cl2 →2NaCl<br />

Amounts of products calculated from the complete reaction of the limiting reagent are called<br />

theoretical yields, whereas the amount actually produced of a product is the actual yield. The ratio of<br />

actual yield to theoretical yield expressed in percentage is called the percentage yield.<br />

percent yield = actual yield / theoretical yield ×100<br />

Chemical reaction equations give the ideal stoichiometric relationship among reactants and products.<br />

Thus, the theoretical yield can be calculated from reaction stoichiometry. For many chemical<br />

reactions, the actual yield is usually less than the theoretical yield, understandably due to loss in the<br />

process or inefficiency of the chemical reaction.<br />

Example 1<br />

Methyl alcohol can be produced in a high-pressure reaction<br />

CO(g) + 2H2(g) →CH3OH(l)<br />

If 6.1 metric tons of methyl alcohol is obtained from 1.2 metric tons of hydrogen reacting with excess<br />

amount of CO, estimate the theoretical and the percentage yield?<br />

Hint:<br />

To calculate the theoretical yield, consider the reaction<br />

CO(g) + 2H2(g) → CH3OH(l)<br />

28.0 + 4.0 = 32.0 (stoichiometric masses in, g, kg, or tons)<br />

1.2 tons H2 × 32.0 CH3OH = 9.6 tons CH3OH<br />

4.0 H2<br />

Thus, the theoretical yield from 1.2 metric tons (1.2x10 6 g) of hydrogen gas is 9.6 tons. The actual<br />

yield is stated in the problem, 6.1 metric tons. Thus, the percentage yield is<br />

103

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