Final NB 2016-2017 Turley

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RULE #3: To add/subtract in scientific notation, the exponents must first be the same. Example: (3.0 x 10 2 ) + (6.4 x 10 3 ); since 6.4 x 10 3 is equal to 64. x 10 2 . Now add. (3.0 x 10 2 ) + (64. x 10 2 ) 67.0 x 10 2 = 6.70 x 10 3 = 6.7 x 10 3 67.0 x 10 2 is mathematically correct, but a number in standard scientific notation can only have one number to the left of the decimal, so the decimal is moved to the left one place and one is added to the exponent. Following the rules for significant figures, the answer becomes 6.7 x 10 3 . RULE #4: To multiply, find the product of the numbers, then add the exponents. Example: (2.4 x 10 2 ) (5.5 x 10 –4 ) = ? [2.4 x 5.5 = 13.2]; [2 + -4 = -2], so (2.4 x 10 2 ) (5.5 x 10 –4 ) = 13.2 x 10 –2 = 1.3 x 10 – 1 RULE #5: To divide, find the quotient of the number and subtract the exponents. Example: (3.3 x 10 – 6 ) / (9.1 x 10 – 8 ) = ? [3.3 / 9.1 = .36]; [-6 – (-8) = 2], so (3.3 x 10 – 6 ) / (9.1 x 10 – 8 ) = .36 x 10 2 = 3.6 x 10 1 18
Convert each number from Scientific Notation to real numbers: 1. 7.485 X 10³ 6. 1.683 X 10⁰ 7485 1.683 2. 8.842 X 10² 7. 3.622 10⁰ 884.2 3.622 3. 2.887 X 10−⁵ 8. 1.735 X 10−⁵ .00002887 .00001735 4. 5.893 X 10−² 9. 9.736 X 10−¹ .05 893 .09736 5. 6.162 X 10−³ 10. 8.558 X 10−² .006162 .08558 Convert each number from a real number to Scientific Notation: 11. 0.0006633 16. 1,937,000 1.6633x10^-4 1.937000x10^6 12. 0.0004445 17. 34,570 4.445x10^-4 3.4570x10^4 13. 0.002182 18. 0.00003948 2.182x10^-4 3.948x10^5 14. 469.5 19. 894,500 4.695x10^2 8.94500x10^5 15. 727,400 20. 678.3 7.27400x10^5 6.783x10^2 19
Page 2 and 3: Honors Chemistry Class Policies and
Page 4 and 5: Unit 1 (22 days) Chapter 1 Introduc
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Bent Molecular Geometry Orbital Equ
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Trigonal Pyramidal Molecular Geomet
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Octahedral Molecular Geometry Orbit
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Orbitals Equation Lone Pairs Angle
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Unit 5 Chapter 10 Chemical Quantiti
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LG:The students will learn how bala
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List what type the following reacti
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Step 5 Balance the hydrogen atoms n
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6) ___ Mn(NO2)2 + ___ BeCl2 ___ Be
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The Learning Goal for this assignme
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Stoichiometry and Balanced Equation
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Step 1: 200g C3H8 is equal to 4.54
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102 Stoichiometry and balanced equa
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%yield = 6.1 tons × 100 = 64% 9.6t
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Use the space provided to write out
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Unit 6 Chapter 13 States of Matter
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LG:The students will learn what are
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13.2 The Nature of Liquids A Model
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114 LG:The students will learn how
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Part 5: Molarity Molarity (M) is th
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The Time-Temperature Graph We are g
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Step Two: solid ice melts Now, we c
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Step Four: liquid water boils Now,
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The following table summarizes the
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The Learning Goal for this section
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10 When a reaction is at equilibriu
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see the credibility to answer D by
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Unit 8 Chapter 19 Acid and Bases Th
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The Learning Goal for this section
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This would be a generic base: XOH -
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154 HCl + H2O ⇌ H3O + + Cl¯ HCl
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Several categories of substances ca
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1. 2.82 2. 8.30 3. 0.00 4. 3.485 5.
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2. What is the oxidation number of
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One point of concern: notice that e
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Reference Tables for Physical Setti
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150. 140. Table G Solubility Curves
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Table I Heats of Reaction at 101.3
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Table O Symbols Used in Nuclear Che
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0 6.941 +1 Li 3 2-1 Na 39.0983 K +1
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First Atomic Symbol Name Ionization
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Collier County CHEMISTRY EXAM FORMU
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CHEMISTRY EXAM FORMULA AND RESOURCE
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Final NB 2016-2017 Turley

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