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CLASS_11_MATHS_SOLUTIONS_NCERT

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Class XI Chapter 4 – Principle of Mathematical Induction Maths<br />

______________________________________________________________________________<br />

<br />

<br />

<br />

<br />

k1 k<strong>11</strong><br />

Thus,<br />

2 2<br />

4<br />

2<br />

k1 k<strong>11</strong><br />

<br />

<br />

2 <br />

<br />

P k 1<br />

<br />

is true whenever<br />

Pk<br />

is true.<br />

Hence, by the principle of mathematical induction, statement<br />

numbers i.e., N.<br />

Pn<br />

is true for all natural<br />

Question 3:<br />

Prove the following by using the principle of mathematical induction for all<br />

1 1 1 2n<br />

1 .....<br />

<br />

1 2 1 2 3 1 2 3 ... n n1<br />

Solution 3:<br />

Let the given statement be<br />

<br />

P n<br />

For<br />

,<br />

P n<br />

i.e.,<br />

1 1 1 2n<br />

:1 ..... <br />

1 2 1 2 3 1 2 3 .... n n1<br />

n 1, we have<br />

2.1 2<br />

P 1 :1 1,<br />

<strong>11</strong> 2<br />

Let<br />

Pk<br />

which is true.<br />

be true for some positive integer k, i.e.,<br />

1 1 1 2k<br />

1 ... .... ....... i<br />

1 2 1 2 3 1 2 3 ..... k k1<br />

We shall now prove that Pk 1<br />

is true.<br />

Consider<br />

1 1 1 1<br />

1 .....<br />

<br />

1 2 1 2 3 1 2 3 ..... k 1 2 3 ..... k k 1<br />

1 1 1 <br />

1<br />

1 ....<br />

<br />

1 2 1 2 3 1 2 3 ..... k 1 2 3 .... k k 1<br />

2k<br />

1<br />

<br />

k 1 1 2 3 ..... k k 1<br />

<br />

<br />

<br />

<br />

[Using (i)]<br />

<br />

<br />

<br />

n<br />

N:

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