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CLASS_11_MATHS_SOLUTIONS_NCERT

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Class XI Chapter 10 – Straight Lines Maths<br />

______________________________________________________________________________<br />

Question 4:<br />

Find a point on the x-axis, which is equidistant from the points (7, 6) and (3, 4).<br />

Solution 4:<br />

Let (a, 0) be the point on the X- axis that is equidistance from the points (7, 6) and (3, 4).<br />

2 2<br />

2 2<br />

Accordingly, 7a 6 0<br />

= 3a 4<br />

0<br />

<br />

2 2<br />

49 a 14a 36 9 a 6a<br />

16<br />

2 2<br />

a 14a 85 a 6a<br />

25<br />

On squaring both sides, we obtain<br />

2 2<br />

a 14a 85 a 6a<br />

25<br />

14a 6a 25 85<br />

8a<br />

60<br />

60 15<br />

a <br />

8 2<br />

15<br />

<br />

Thus, the required point on the x-axis is ,0<br />

2<br />

<br />

<br />

Question 5:<br />

Find the slope of a line, which passes through the origin, and the mid-point of the segment<br />

joining the points P (0, -4) and B (8, 0).<br />

Solution 5:<br />

The coordinates of the mid-point of the line segment joining the points<br />

08 4 0<br />

<br />

P (0, -4) and B (8, 0) are , (4, 2)<br />

2 2<br />

<br />

<br />

It is known that the slope (m) of a non-vertical line passing through the points (x1, y1) and (x2,<br />

y2<br />

y1<br />

y2) is given by m , x2 x1<br />

x x<br />

2 1<br />

Therefore, the slope of the line passing through (0, 0,) and (4, -2) is<br />

Hence, the required slope of the line is<br />

1<br />

.<br />

2<br />

2 0 2 1<br />

<br />

40 4 2<br />

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