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CLASS_11_MATHS_SOLUTIONS_NCERT

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Class XI Chapter 10 – Straight Lines Maths<br />

______________________________________________________________________________<br />

3<br />

cos = -<br />

2 , sin = 1<br />

, and p =1<br />

2<br />

7<br />

Since the value of sin and cos are negative, <br />

6 6<br />

Thus, the respective values of and p are 7 and 1.<br />

6<br />

Question 3:<br />

Find the equation of the line, which cut-off intercepts on the axes whose sum and product are 1<br />

and -6, respectively.<br />

Solution 3:<br />

Let the intercepts cut by the given lines on the axes be a and b.<br />

It is given that<br />

a + b = 1 …(1)<br />

ab = -6 …(2)<br />

On solving equations (1) and (2) , we obtain<br />

a = 3 and b = -2 or a = -2 and b = 3<br />

It is known that the equation of the line whose intercepts on the axes are a and b is<br />

x y<br />

1 or bx + ay – ab = 0<br />

a b<br />

Case I: a = 3 and b = -2<br />

In case, the equation of the line is -2x + 3y + 6 = 0, i.e., 2x – 3 y = 6.<br />

Case II: a = - 2 and b = 3<br />

In this case, the equation of the line is 3x – 2y + 6 = 0, i.e., -3x + 2y = 6.<br />

Thus, the required equation of the lines are 2x – 3 y = 6 and -3x + 2y = 6.<br />

Question 4:<br />

x y<br />

What are the points on the y-axis whose distance from line 1is 4 units.<br />

3 4<br />

Solution 4:<br />

x y<br />

Let (0, b) be the point on y-axis whose distance from line 1 is 4 units.<br />

3 4<br />

The given line can be written as 4x + 3y – 12 = 0 …(1)<br />

On comparing equation (1) to the general equation of line Ax + By + C = 0, we obtain A = 4, B<br />

= 3, C = -12.<br />

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