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CLASS_11_MATHS_SOLUTIONS_NCERT

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Class XI Chapter 15 – Statistics Maths<br />

______________________________________________________________________________<br />

Question 2:<br />

The mean and variance of 7 observations are 8 and 16, respectively. If five of the observations<br />

are 2, 4, 10, 12 and 14. Find the remaining two observations.<br />

Solution 2:<br />

Let the remaining two observations be x and y.<br />

The observations are 2, 4, 10, 12, 14, x, y.<br />

2+4+10+12+14+x+y<br />

Mean, x= 8<br />

7<br />

56 42 x<br />

y<br />

<br />

x y14 ...... 1<br />

1<br />

7<br />

2<br />

Variance=16= x<br />

n<br />

i x<br />

i1<br />

1<br />

2 2<br />

16 6 4 2 4 6 x y 28 x y 2<br />

8<br />

7 <br />

1<br />

2 2<br />

16 36 16 4 16 36 1614 264<br />

7 x y <br />

<br />

..... using 1<br />

<br />

1<br />

2 2<br />

16 108 224 128<br />

7 x y <br />

<br />

1 2 2<br />

16 12<br />

x y <br />

7 <br />

2 2<br />

x y <strong>11</strong>2 12 100<br />

2 2<br />

x y <br />

<br />

2 2 2 2 2 2<br />

<br />

100 .... 2<br />

From (1), we obtain<br />

x2 + y2 + 2xy = 196 … (3)<br />

From (2) and (3), we obtain<br />

2xy = 196 – 100<br />

⇒ 2xy = 96 … (4)<br />

Subtracting (4) from (2), we obtain<br />

x2 + y2 – 2xy = 100 – 96<br />

⇒ (x – y)2 = 4<br />

⇒ x – y = ± 2 … (5)<br />

Therefore, from (1) and (5), we obtain<br />

x = 8 and y = 6 when x – y = 2<br />

x = 6 and y = 8 when x – y = – 2<br />

Thus, the remaining observations are 6 and 8.<br />

<br />

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