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CLASS_11_MATHS_SOLUTIONS_NCERT

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Class XI Chapter 9 – Sequences and Series Maths<br />

______________________________________________________________________________<br />

Question 3:<br />

The 5 th , 8 th and <strong>11</strong> th terms of a G.P. are<br />

Solution 3:<br />

Let a be the first term and r<br />

a a r a r p<br />

<br />

51 4<br />

5<br />

........ 1<br />

a a r a r q<br />

<br />

81 7<br />

8<br />

........ 2<br />

a a r a r s<br />

<br />

<strong>11</strong>1 10<br />

<strong>11</strong><br />

........ 3<br />

Dividing equation (2) by (1), we obtain<br />

a r<br />

a r<br />

r<br />

3<br />

7<br />

4<br />

q<br />

<br />

p<br />

q<br />

<br />

p<br />

<br />

....... 4<br />

Dividing equation (3) by (2), we obtain<br />

a r<br />

a r<br />

10<br />

7<br />

r<br />

3<br />

s<br />

<br />

q<br />

s<br />

<br />

q<br />

Equating the values of<br />

q s<br />

<br />

p q<br />

q<br />

2<br />

ps<br />

<br />

...... 5<br />

3<br />

r<br />

Thus, the given result is proved.<br />

pq ,<br />

and s , respectively. Show that<br />

2<br />

q<br />

ps<br />

be the common ratio of the G.P. According to the given condition,<br />

obtained in (4) and (5), we obtain<br />

.<br />

Question 4:<br />

The 4 th term of a G.P. is square of its second term, and the first term is<br />

term.<br />

Solution 4:<br />

Let a be the first term and r be the common ratio of the G.P.<br />

a 3<br />

It is known that,<br />

<br />

an<br />

a ar r<br />

3 3<br />

4<br />

3<br />

a a r r<br />

<br />

1<br />

2<br />

3<br />

<br />

<br />

ar <br />

n 1<br />

According to the given condition,<br />

3. Determine its 7 th<br />

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