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CLASS_11_MATHS_SOLUTIONS_NCERT

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Class XI Chapter 5 – Complex Numbers and Quadratic Equations Maths<br />

______________________________________________________________________________<br />

r 4 2<br />

<br />

Modulus = 2<br />

2cos<br />

3<br />

<br />

<br />

and 2sin 1<br />

3 1<br />

cos<br />

and sin<br />

<br />

2 2<br />

5<br />

<br />

<br />

6 6<br />

Conventionally, r 0<br />

Thus, the modulus an argument of the complex number<br />

<br />

[As lies in the II quadrant]<br />

<br />

3 i<br />

are 2 and<br />

5<br />

6<br />

respectively.<br />

Question 3:<br />

Convert the given complex number in polar form: 1 i<br />

Solution 3:<br />

1i<br />

r cos 1<br />

r sin 1<br />

Let and<br />

On squaring and adding, we obtain<br />

r<br />

2 2 2 2 2<br />

2<br />

cos r sin 1 1<br />

<br />

2 2 2<br />

r <br />

r<br />

2<br />

cos sin 1 1<br />

2<br />

<br />

r 2 Conventionally, r<br />

0<br />

<br />

2 cos<br />

1<br />

cos<br />

<br />

<br />

<br />

4<br />

1<br />

2<br />

and<br />

and<br />

<br />

2 sin 1<br />

sin <br />

1<br />

<br />

2<br />

<br />

<br />

As liesin the IV quadrant<br />

<br />

1i r cos<br />

i r sin<br />

2 cos i 2 sin 2 cos isin<br />

<br />

4 4<br />

<br />

4 4<br />

<br />

<br />

This is the required polar form.

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