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CLASS_11_MATHS_SOLUTIONS_NCERT

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Class XI Chapter 10 – Straight Lines Maths<br />

______________________________________________________________________________<br />

3k 0 3h<br />

y0<br />

x<br />

3h<br />

<br />

0<br />

2<br />

<br />

<br />

2<br />

2k<br />

3h<br />

y x<br />

h<br />

<br />

2<br />

<br />

<br />

hy 2kx 3hk<br />

i. e.,2kx hy 3hk<br />

Thus, the required equation of a line is 2kx hy 3hk<br />

Question 20:<br />

By using the concept of equation of a line, prove that the three points (3, 0), (-2, -2) and (8, 2)<br />

are collinear.<br />

Solution 20:<br />

In order to show that the points (3, 0), (-2, -2) and (8, 2) are collinear, it suffices to show that<br />

the line passing through points (3, 0) and (-2, -2) also passes through point (8, 2).<br />

The equation of the line passing through points (3, 0) and (-2, -2) is<br />

20<br />

y0<br />

x3<br />

23<br />

<br />

2<br />

y<br />

x3<br />

5<br />

5y2x6<br />

i.e., 2x-5y=6<br />

It is observed that at x = 8 and y= 2,<br />

L.H.S = 28-5 2=16-10=6=R.H.S .<br />

Therefore, the line passing through points (3, 0) and (-2, -2) also passes through point (8, 2).<br />

Hence, points (3, 0), (-2, -2), and (8, 2) are collinear.<br />

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