CLASS_11_MATHS_SOLUTIONS_NCERT

Class XI Chapter 11 – Conic Section Maths
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axis.
Accordingly, a = 3 and b = 2.
Thus, the equation of the ellipse is
x
y x y
1 or 1.
2 2 2 2
2 2
3 2 9 4
Question 14:
Find the equation for the ellipse that satisfies the given conditions: Ends of major axis
ends of minor axis ( ±1, 0)
Solution 14:
Ends of major axis0, 5 , ends of minor axis (±1, 0)
Here, the major axis is along the y-axis.
x
Therefore, the equation of the ellipse will be of the form
b
axis.
Accordingly, a 5 = and b = 1.
Thus, the equation of the ellipse is
x
y
a
2 2
2 2
y x
1 or
y
1
5
2 2 2 2
2
2
1 1 5
0, 5
1 , where a is the semi-major
Question 15:
Find the equation for the ellipse that satisfies the given conditions: Length of major axis 26, foci
(±5, 0)
Solution 15:
Length of major axis = 26; foci = (±5, 0).
Since the foci are on the x-axis, the major axis is along the x-axis.
Therefore, the equation of the ellipse will be of the form
axis.
Accordingly, 2a = 26 ⇒ a = 13 and c = 5.
It is known that a 2 = b 2 + c 2 .
x
a
y
b
2 2
2 2
1, where a is the semi-major
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