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CLASS_11_MATHS_SOLUTIONS_NCERT

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Class XI Chapter 15 – Statistics Maths<br />

______________________________________________________________________________<br />

Question 6:<br />

Find the mean and standard deviation using short-cut method.<br />

x 60 61 62 63 64 65 66 67 68<br />

i<br />

f 2 1 12 29 25 12 10 4 5<br />

i<br />

Solution 6:<br />

The data is obtained in tabular form as follows.<br />

x<br />

i<br />

f<br />

x<br />

i<br />

i<br />

64<br />

2<br />

y fy<br />

1<br />

i i<br />

f<br />

<br />

i<br />

1<br />

60 2 –4 16 –8 32<br />

61 1 –3 9 –3 9<br />

62 12 –2 4 –24 48<br />

63 29 –1 1 –29 29<br />

64 25 0 0 0 0<br />

65 12 1 1 12 12<br />

66 10 2 4 20 40<br />

67 4 3 9 12 36<br />

68 5 4 16 20 80<br />

100 220 0 286<br />

9<br />

<br />

i i<br />

i<br />

Mean, 1fy 0<br />

x=A h=64+ 1 64 0 64<br />

N 100<br />

2 9 9<br />

2 h 2 2 <br />

Variance, N f<br />

2 iy <br />

i<br />

fiy<br />

<br />

i<br />

N <br />

<br />

i1 i1<br />

<br />

<br />

1<br />

<br />

2<br />

100 286 0 <br />

100<br />

2.86<br />

= 2.86 1.69<br />

Standard deviation <br />

fi<br />

2<br />

y 1<br />

Question 7:<br />

Find the mean and variance for the following frequency distribution.<br />

Classes 0-30 30-60 60-90 90-120 120-150 150-180 180-210<br />

Frequencies 2 3 5 10 3 5 2<br />

Solution 7:<br />

Class Frequency<br />

f<br />

i<br />

Mid-point x<br />

i<br />

xi<br />

105<br />

yi<br />

<br />

30<br />

2<br />

y<br />

i<br />

fi<br />

y<br />

i<br />

fi<br />

2<br />

y<br />

i<br />

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