14.02.2018 Views

CLASS_11_MATHS_SOLUTIONS_NCERT

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

Class XI Chapter 9 – Sequences and Series Maths<br />

______________________________________________________________________________<br />

<br />

2 2<br />

a b a b 4ab 36ab 4ab 32ab<br />

a b 32 ab<br />

<br />

4 2 ab ...... 2<br />

Adding (1) and (2), we obtain<br />

<br />

2 a 6 4 2<br />

a <br />

<br />

32 2<br />

<br />

<br />

ab<br />

ab<br />

Substituting the value of a<br />

<br />

b 6 ab 3 2 2 ab<br />

<br />

b 3<br />

2 2<br />

a<br />

b<br />

<br />

<br />

<br />

<br />

<br />

<br />

ab<br />

3<br />

2 2 ab 3<br />

2 2<br />

<br />

3<br />

2 2 ab 3 2 2<br />

in (1), we obtain<br />

Thus, the required ratio is <br />

32 2 : 32 2<br />

.<br />

Question 29:<br />

If A and G be A.M. and G.M., respectively between two positive numbers, prove that the<br />

numbers are<br />

Solution 29:<br />

A A G A G<br />

It is given that A and G are A.M. and G.M. between two positive numbers.<br />

Let these two positive numbers be a and b .<br />

a<br />

b<br />

AM A <br />

2<br />

GM G ab<br />

<br />

..... 1<br />

.... 2<br />

From (1) and (2), we obtain<br />

a b 2 A ..... 3<br />

ab<br />

G<br />

2<br />

<br />

....... 4<br />

Substituting the value of a and b<br />

<br />

2 2<br />

a b a b 4ab<br />

,<br />

We obtain<br />

a b 2 4A 2 4G 2 4 A 2 G<br />

2<br />

<br />

from (3) and (4) in the identity<br />

Printed from Vedantu.com. Register now to book a Free LIVE Online trial session with a<br />

Top tutor.

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!