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Analisis Multivariado 1 (Apunte basado en notas de clases del ...

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X 2<br />

Distancia <strong>de</strong> Mahalanobis<br />

E<br />

14.1 Descomposicion <strong>de</strong> la Distancia <strong>de</strong> Mahalanobis<br />

Let T 2 be the Mahalanobis distance, the MYT <strong>de</strong>composition is<br />

C 1<br />

T 2 = T 2 1 +T 2 2/1 + T 2 3/1,2 + T 2 4/1,2,3 + . . . + T 2 p/1,2,3,4,...,p−1<br />

where the first and last term are<br />

T 2<br />

1 = (x1−x2 1 )2<br />

S2 2<br />

Tp/1,2,3,4,...,p−1 1 and =<br />

(xp−x 2 p/1,2,3,4,...,p−1 )2<br />

S2 p/1,2,3,4,··· ,p−1<br />

We <strong>de</strong>fine the contribution of variable p to the distance as<br />

Cp =<br />

T 2<br />

p/1,2,3,4,...,p−1<br />

T 2<br />

because all terms are positive, the contribution satisfies<br />

0 ≤ Cp ≤ 1<br />

From now on we will call<br />

If in a certain day happ<strong>en</strong>s that T 2 is big, and T 2 p/1,2,3,4,...,p−1 is<br />

close to 1, th<strong>en</strong> the station/variable p is wrong, because<br />

T 2 j/Aj<br />

is small<br />

for all j∈ {1, 2, 3, 4, . . . , p − 1} and Aj ⊆ {1, 2, 3, 4, . . . , j − 1, j + 1, . . . , p − 1}<br />

The p relevant <strong>de</strong>compositions are<br />

T 2 = T 2 2 +T 2 3/2 + T 2 4/2,3 + T 2 5/2,3,4 + . . . + T 2 1/2,3,4,...,p<br />

T 2 = T 2 1 +T 2 3/1 + T 2 4/1,3 + T 2 5/1,3,4 + . . . + T 2 2/1,3,4,...,p<br />

T 2 = T 2 1 +T 2 2/1 + T 2 4/1,2 + T 2 5/1,2,4 + . . . + T 2 3/1,2,4,...,p<br />

.<br />

T 2 = T 2 1 +T 2 2/1 + T 2 3/1,2 + T 2 4/1,2,3 + . . . + T 2 p−1/1,2,3,4,...,p−2,p<br />

T 2 = T 2 1 +T 2 2/1 + T 2 3/1,2 + T 2 4/1,2,3 + . . . + T 2 p/1,2,3,4,...,p−1<br />

28<br />

C 2<br />

X 1

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