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Fluid Mechanics and Thermodynamics of Turbomachinery, 5e

Fluid Mechanics and Thermodynamics of Turbomachinery, 5e

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Two-dimensional Cascades 77<br />

FIG. 3.18. Variation <strong>of</strong> nominal deflection with nominal outlet angle for several<br />

space–chord ratios (adapted from Howell 1945a <strong>and</strong> 1945b).<br />

important that an accurate estimate is made <strong>of</strong> it. Re-examining Figure 3.11, it will be<br />

observed that the fluid receives its maximum guidance on the pressure side <strong>of</strong> the<br />

cascade channel <strong>and</strong> that this diminishes almost linearly towards the suction side <strong>of</strong> the<br />

channel.<br />

Howell used an empirical rule to relate nominal deviation d* to the camber <strong>and</strong><br />

space–chord ratio,<br />

(3.39)<br />

where n 1 – 2 for compressor cascades <strong>and</strong> n 1 for compressor inlet guide vanes.<br />

The value <strong>of</strong> m depends upon the shape <strong>of</strong> the camber line <strong>and</strong> the blade setting. For<br />

a compressor cascade (i.e. diffusing flow),<br />

(3.40a)<br />

where a is the distance <strong>of</strong> maximum camber from the leading edge. For the inlet guide<br />

vanes, which are essentially turbine nozzles (i.e. accelerating flow),<br />

(3.40b)<br />

EXAMPLE 3.1. A compressor cascade has a space–chord ratio <strong>of</strong> unity <strong>and</strong> blade inlet<br />

<strong>and</strong> outlet angles <strong>of</strong> 50deg <strong>and</strong> 20deg respectively. If the blade camber line is a circular<br />

arc (i.e. a/l = 50%) <strong>and</strong> the cascade is designed to operate at Howell’s nominal<br />

condition, determine the fluid deflection, incidence <strong>and</strong> ideal lift coefficient at the<br />

design point.<br />

Solution. The camber, q = a¢ 1 - a¢2 = 30deg. As a first approximation put a* 2<br />

= 20deg in eqn. (3.40) to give m = 0.27 <strong>and</strong>, using eqn. (3.39), d* = 0.27 ¥ 30 =<br />

8.1deg. As a better approximation put a* 2 = 28.1deg in eqn. (3.40) giving m = 0.2862<br />

<strong>and</strong> d* = 8.6 deg. Thus, a* 2 = 28.6deg is sufficiently accurate.

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