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Fluid Mechanics and Thermodynamics of Turbomachinery, 5e

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156 <strong>Fluid</strong> <strong>Mechanics</strong>, <strong>Thermodynamics</strong> <strong>of</strong> <strong>Turbomachinery</strong><br />

The pressure rise in a real stage (involving irreversible processes) can be determined<br />

if the stage efficiency is known. Defining the stage efficiency hs as the ratio <strong>of</strong> the isentropic<br />

enthalpy rise to the actual enthalpy rise corresponding to the same finite pressure<br />

change, (cf. Figure 2.7), this can be written as<br />

Thus,<br />

(5.27)<br />

If c1 = c3, then hs is a very close approximation <strong>of</strong> the total-to-total efficiency htt.<br />

Although the above expressions are derived for incompressible flow they are, nevertheless,<br />

a valid approximation for compressible flow if the stage temperature (<strong>and</strong> pressure)<br />

rise is small.<br />

Pressure ratio <strong>of</strong> a multistage compressor<br />

It is possible to apply the preceding analysis to the determination <strong>of</strong> multistage compressor<br />

pressure ratios. The procedure requires the calculation <strong>of</strong> pressure <strong>and</strong> temperature<br />

changes for a single stage, the stage exit conditions enabling the density at entry<br />

to the following stage to be found. This calculation is repeated for each stage in turn<br />

until the required final conditions are satisfied. However, for compressors having identical<br />

stages it is more convenient to resort to a simple compressible flow analysis. An<br />

illustrative example is given below.<br />

EXAMPLE 5.1. A multistage axial compressor is required for compressing air at 293<br />

K, through a pressure ratio <strong>of</strong> 5 to 1. Each stage is to be 50% reaction <strong>and</strong> the mean<br />

blade speed 275m/s, flow coefficient 0.5, <strong>and</strong> stage loading factor 0.3, are taken, for<br />

simplicity, as constant for all stages. Determine the flow angles <strong>and</strong> the number <strong>of</strong> stages<br />

required if the stage efficiency is 88.8%. Take Cp = 1.005kJ/(kg°C) <strong>and</strong> g = 1.4 for air.<br />

Solution. From eqn. (5.14a) the stage load factor can be written as<br />

From eqn. (5.11) the reaction is<br />

Solving for tan b 1 <strong>and</strong> tan b 2 gives<br />

Calculating b1 <strong>and</strong> b 2 <strong>and</strong> observing for R = 0.5 that the velocity diagram is<br />

symmetrical,<br />

Writing the stage load factor as y = CpDT0/U 2 , then the stage stagnation temperature<br />

rise is

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