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multiple time scale dynamics with two fast variables and one slow ...

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This explicit solution provides a benchmark for evaluating the accuracy of the<br />

algorithm described above. The <strong>slow</strong> manifold of the system is the line{y=<br />

x1+ǫ, x2= 0} containing the trajectories (x1, x2, y)(t)=(y(0)−ǫ+ t, 0, y(0)+t).<br />

The discretized equations of the algorithm can also be solved explicitly for<br />

system (4.3). The first step in doing so is to observe that the equations for x1 <strong>and</strong><br />

y are separable from those for x2, <strong>and</strong> this remains the case for the discretized<br />

equations of the boundary value solver. Substituting the equations for the y-<br />

variable into the boundary value equations produces the equation y j+1− y j =<br />

t j+1− t j on each mesh interval. If a boundary condition is imposed on <strong>one</strong> end<br />

of the <strong>time</strong> interval [a, b], these equations yield a solution that is a discretization<br />

of an exact solution of the differential equation. Convergence occurs in a single<br />

step.<br />

Assume now that y j+1− y j = t j+1− t j <strong>and</strong> set w j = y j− (x1) j−ǫ to be the<br />

difference between the x1 coordinate of a point <strong>and</strong> a point of the <strong>slow</strong> manifold.<br />

The boundary value equations become<br />

δ 2 − 6δǫ+ 12ǫ 2<br />

8δǫ 2<br />

w j− δ2 + 6δǫ+ 12ǫ 2<br />

8δǫ 2 w j+1= 0 (4.4)<br />

for a uniform mesh <strong>with</strong>δ=y j+1−yj= t j+1−tj. The boundary conditions at t0= a<br />

must be transverse to the x1 coordinate axis which is E s . Therefore, we choose to<br />

fix the value of x1 as the boundary condition at t0= a. Note that these equations<br />

are satisfied when the w j vanish, so if the value of x1 is y−ǫ at t0=a, the w j<br />

yield a discretization of the exact solution along the <strong>slow</strong> manifold. Solving the<br />

equation (4.4) for w j+1 in terms of w j yields<br />

w j+1= δ2 − 6δǫ+ 12ǫ 2<br />

δ 2 + 6δǫ+ 12ǫ 2 w j<br />

Like the solutions of the differential equation, the values w j decrease exp<strong>one</strong>n-<br />

tially as a function of <strong>time</strong>. The ratioρ j=w j+1/w j is a function of (δ/ǫ) whose<br />

104

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