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multiple time scale dynamics with two fast variables and one slow ...

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This result can be written more compactly in vector form as:<br />

From Lemma 2.5.1 we get that<br />

<br />

<br />

<br />

<br />

<br />

η2<br />

Z1<br />

ˆX ′ = (B−Λ) ˆX+<br />

η2<br />

Z1<br />

− η11<br />

Z1<br />

<br />

ˆX<br />

<br />

<br />

<br />

<br />

≤ Ĉ|a| ˆX+ ˆK(ǫ+|b|)(1+ ˆZ+ˆX)<br />

Since we have already found an estimate on|η11/Z1| above it now follows that<br />

where<br />

<br />

<br />

<br />

<br />

<br />

η2<br />

Z1<br />

− η11<br />

Z1<br />

<br />

<br />

ˆX<br />

<br />

<br />

≤β3(t) ˆX+β2(t) (2.34)<br />

β3(t)=C ∗ |a|(1+ˆX)+ K(ǫ+|b|)<br />

<strong>and</strong> the constants are chosen so that C ∗ > ˜C+ǫ ˜K+ ˜C <strong>and</strong> K> max( ˜K, ˆK). Basi-<br />

cally the estimate (2.34) controls the nonlinear term for the equations of ˆX. We<br />

proceed by considering an integrating factor:<br />

<br />

J(t) := exp −<br />

t<br />

0<br />

<br />

(B−ΛId)ds<br />

The st<strong>and</strong>ard integrating factor calculation then reads<br />

ˆX ′ J− (B−Λ) ˆXJ=J<br />

⇒ ( ˆXJ) ′ <br />

η2<br />

= J − η11<br />

<br />

ˆX<br />

⇒<br />

t<br />

0<br />

( ˆXJ) ′ ds=<br />

η2<br />

Z1<br />

− η11<br />

Z1<br />

Z1 Z1<br />

t <br />

η2<br />

J −<br />

0 Z1<br />

η11<br />

Z1<br />

t <br />

η2<br />

⇒ ˆX=J(t) −1 ˆX0+J(t) −1<br />

The inverse of the matrix J(t) is<br />

0<br />

J<br />

Z1<br />

J(t) −1 t <br />

= exp (B−ΛId)ds<br />

0<br />

48<br />

<br />

ˆX<br />

<br />

ˆX ds<br />

− η11<br />

Z1<br />

<br />

ˆX ds

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