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Pictures Paths Particles Processes

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108 November 7, 2013<br />

Note that the connected blobs may themselves contain many different individual<br />

diagrams. By separating the blobs A and B we indicate that the unstable<br />

particles is actually quite long-lived so that the place where it is produced and<br />

that where it decays tend to be clearly separated.<br />

Now, we shall assume that we have somehow solved the problem of how to<br />

go from connected Green’s function to amplitude, and that we have applied this<br />

procedure to the above process. We then have for the amplitude the form<br />

M = [A]<br />

i¯h<br />

p 2 − m 2 [B] , (4.5)<br />

+ imΓ<br />

where p = q 1 + · · · + q n is the momentum of the (internal!) line corresponding<br />

with the unstable particle, and p 2 = p·p. The unstable particle’s mass is m, and<br />

its total decay width is Γ. The symbols [A] and [B] stand for the processed connected<br />

Green’s functions for the ‘production’ process A and the ‘decay’ process<br />

B, but with the Feynman factors for the unstable particle removed. Assuming,<br />

for simplicity, that F symm = 1, we then have for the differential cross section the<br />

form<br />

dσ = Φ σ |[A]| 2 |[B]| 2 ¯h 2<br />

(p 2 − m 2 ) 2 + m 2 Γ 2 dV (P ; k 1, . . . , k j , q 1 , . . . , q n ) , (4.6)<br />

where P = p a + p b . In order to emphasize that p is the sum of the q’s, we may<br />

write this also as<br />

dσ = Φ σ |[A]| 2 |[B]| 2 dV (P ; k 1 , . . . , k j , q 1 , . . . , q n )<br />

¯h 2<br />

(p 2 − m 2 ) 2 + m 2 Γ 2 d 4 p<br />

(2π) 4 (2π)4 δ 4 (p − Σq) , (4.7)<br />

with obvious notation for the sum over the wavevectors q.<br />

Now, we let the unstable particle approach stability, so that the location<br />

where it decays becomes widely separated from that where it is produced. That<br />

is, we examine the case that Γ becomes very, very small, and we may approximate<br />

7 1<br />

(p 2 − m 2 ) 2 → π<br />

+ m 2 Γ 2 mΓ δ(p2 − m 2 ) . (4.8)<br />

We can then use this to rewrite<br />

dV (P ; k 1 , . . . , k j , q 1 , . . . , q n )<br />

(p 2 − m 2 ) 2 + m 2 Γ 2 d 4 p<br />

(2π) 4 (2π)4 δ 4 (p − Σq) (4.9)<br />

7 This follows from the well-known representation of the Dirac delta function as<br />

1<br />

δ(x) = lim<br />

z→0 π<br />

which has unit integral and vanishes for every x ≠ 0.<br />

z<br />

x 2 + z 2 ,

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