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112 November 7, 2013<br />

The n-particle phase-space integration element dV n has dimensionality L 4−2n<br />

as we have seen. Taking into account that the flux factor Φ Γ = 1/2m must have<br />

the dimensionality of 1/m, that is, L, the dimensionality of the decay width of<br />

a single particle into n particles is given by<br />

[ ] [ ]<br />

]<br />

1<br />

dim Γ(1 → n) = dim<br />

m (M n+1) 2 dV n = dim<br />

[L −1<br />

, (4.20)<br />

as required. Similarly, for the cross section of two particles going into n particles<br />

we have<br />

[ ] [ ( ]<br />

2 ]<br />

1<br />

dim σ(2 → n) = dim (M n+2 )<br />

m) 2 dV n = dim<br />

[L 2 , (4.21)<br />

again as required. Note that the above analysis is kept simple because we have<br />

restricted ourselves to the use of wavevectors rather than mechanical momenta,<br />

which would introduce additional factors of ¯h in the calculation. The other<br />

natural constant, c, need not enter here.<br />

4.3.4 Crossing symmetry<br />

In our treatment of antimatter in the previous chapter we have seen that the<br />

production (absorption) of a particle is, in a sense, æquivalent to the absorption<br />

(production) of its antiparticle. We can make this even more specific as a relation<br />

between various scattering amplitudes : this goes by the name of crossing<br />

symmetry. Consider a generic 2 → 2 scattering process :<br />

a(p 1 ) + b(p2) → c(q1) + d(q2)<br />

where we have indicated the momenta of the particles. Let us write the corresponding<br />

amplitude as M(p 1 , p 2 , q 1 , q 2 ). By moving particles from the initial to<br />

the final state 10 , or vice versa, we can then find the amplitudes for the crossingrelated<br />

processes, for example :<br />

a + b → c + d : M(p 1 , p 2 , q 1 , q 2 ) ,<br />

a + ¯c → ¯b + d : M(p 1 , −p 2 , −q 1 , q 2 ) ,<br />

a + ¯d → ¯b + c : M(p 1 , −p 2 , q 1 , −q 2 ) ,<br />

¯c + ¯d → ā + ¯b : M(−p 1 , −p 2 , −q 1 , −q 2 ) . (4.22)<br />

Since the momenta of all (anti)particles have positive energy, the minus signs<br />

yield momenta with negative energy. Depending on the type of the particle 11 ,<br />

this may involve an analytic continuation of the amplitude function M.<br />

10 You can visualize this by taking an outgoing particle, say, and dragging its external leg<br />

from the final to the initial state.<br />

11 Especially for Dirac particles.

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