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November 7, 2013 129<br />

Before finishing this section, let us introduce the Feynman ‘slash’ notation :<br />

if a µ is a Lorentz vector, we shall mean by /a its contraction with Dirac matrices:<br />

/a ≡ a µ γ µ . (5.11)<br />

The Dirac equation (5.7) can therefore also be written as 9<br />

with the corollary that<br />

/a/b + /b/a = 2 (a · b) ∀ a µ , b ν , (5.12)<br />

/a/a = a 2 . (5.13)<br />

We stress that the vector object a µ and the matrix /a encode exactly the same<br />

information ; further on we shall see how the vector can be recovered once<br />

the matrix is given. A few simple results, which can be checked by repeated<br />

application of the anticommutation rule, are<br />

5.2.2 The Clifford algebra<br />

γ µ /a γ µ = −2 /a ,<br />

γ µ /a /b γ µ = 4(a · b) . (5.14)<br />

By the anticommutation relation (5.7), any product of more than four Dirac<br />

matrices can be reduced to a smaller number. Let us define the enormously<br />

useful object 10 γ 5 ≡ i γ 0 γ 1 γ 2 γ 3 , (5.15)<br />

for which we can immediately derive that<br />

γ 5 γ µ = −γ µ γ 5 , (γ 5 ) 2 = 1 . (5.16)<br />

Also we can define the commutator of Dirac matrices as<br />

σ µν ≡ i 2 [γµ , γ ν ] = i 2 (γµ γ ν − γ ν γ µ ) . (5.17)<br />

Obviously there are 6 independent σ matrices. The most general object that<br />

can be constructed using Dirac matrices is therefore<br />

Γ = S 1 + V µ γ µ + T µν σ µν + A µ γ 5 γ µ + P γ 5 , (5.18)<br />

and these objects form the Clifford algebra. We see that T (p) must be an<br />

element of the Clifford algebra. The various coefficients are called, repectively,<br />

the scalar (S), vector (V µ ), tensor (T µν ), axial-vector (A µ ) and pseudo-scalar<br />

9 It is customary to leave the unit matrix 1 out of the notation. Its presence can always be<br />

inferred where necessary.<br />

10 In some texts the definition of γ 5 is slightly different, for instance it may lack the factor<br />

i. Some care is necessary in comparing results between different texts. The reason why it is<br />

called γ 5 and not γ 4 is that in some older treatments the Minkowski indices were assumed to<br />

run from 1 to 4, with the 4 th index playing the rôle of our 0 th one.

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