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November 7, 2013 261<br />

Here, the B n are the Bernoulli numbers, defined by their generating function as<br />

follows :<br />

F (x) ≡<br />

x ex<br />

e x − 1 = ∑ x n<br />

B n . (10.37)<br />

n!<br />

n≥0<br />

It is easily seen that B 0 = 1 and B 1 = 1/2 ; but more significantly, from the fact<br />

that F (x) − x/2 is actually 7 even in x, we see that all B n vanish for odd n ≥ 3 ;<br />

which again means that all odd loop corrections beyond the first order vanish<br />

for all Green’s functions ! The receipe is even simpler than in the previous<br />

case : replacing each vertex by −1 and each propagator by 1, all odd-loop<br />

Green’s functions must be identically zero ; yet another powerful check on our<br />

computations.<br />

7 From the way it is written, this seems unlikely — but it is true.

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