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November 7, 2013 135<br />

5.3 Dirac particles<br />

5.3.1 Dirac spinors<br />

The requirements on the object T (p) that we have gathered so far are that it<br />

be a member of the Clifford algebra, and that<br />

T (p) 2 = T (p) , T (p) = T (p) , (5.57)<br />

although by a renormalization we may relax the first requirement into a proportionality.<br />

Now, it must be remembered that any modification of the propagator<br />

may be compensated for by a transformation of the vertices : so, if there is a<br />

Clifford-algebra object Σ such that<br />

then, effectively, the propagator<br />

ΣΣ = ΣΣ = 1 ,<br />

Σ T (p) Σ<br />

is equivalent to T (p) itself. We may then perform a search 18 through all inequivalent<br />

possibilities for T . The upshot is that there are precisely four projection<br />

operators, for a choice of two Minkowski vectors k µ and s µ such that<br />

k · k = 1 , s · s = −1 , k · s = 0 , (5.58)<br />

and they read<br />

Π(λ 1 , λ 2 ) = 1 4<br />

( ) ( )<br />

1 + λ 1 /k 1 + λ 2 γ 5 /s<br />

, (5.59)<br />

where λ 1,2 = ±1. We have<br />

and<br />

Π(λ 1 , λ 2 ) = Π(λ 1 , λ 2 ) (5.60)<br />

Π(λ 1 , λ 2 )Π(λ ′ 1, λ ′ 2) = δ λ1,λ ′ 1 δ λ 2,λ ′ 2 Π(λ 1, λ 2 ) (5.61)<br />

and also we conclude that, since there are precisely 4 projection operators,<br />

we can settle for N = 4 for the Dirac matrices 19 . Since for on-shell particles<br />

18 This is a quite tedious task, in particular the unearthing of the necessary Σ matrices.<br />

This is relegated to Appendix 8, based on the efforts of J. de Groot.<br />

19 This presupposes that a four-dimensional choice of dirac matrices is actually possible.<br />

This is the case, witness the so-called Pauli representation :<br />

⎛<br />

γ 0 = ⎝<br />

⎛<br />

γ 2 = ⎝<br />

1 0 0 0<br />

0 1 0 0<br />

0 0 −1 0<br />

0 0 0 −1<br />

0 0 0 −i<br />

0 0 i 0<br />

0 i 0 0<br />

−i 0 0 0<br />

⎞<br />

⎛<br />

⎠ , γ 1 = ⎝<br />

⎞<br />

⎛<br />

⎠ , γ 3 = ⎝<br />

0 0 0 1<br />

0 0 1 0<br />

0 −1 0 0<br />

−1 0 0 0<br />

0 0 1 0<br />

0 0 0 −1<br />

−1 0 0 0<br />

0 1 0 0<br />

Any other representation will do as well: that is the whole point of it !<br />

⎞<br />

⎠ ,<br />

⎞<br />

⎠ . (5.62)

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