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November 7, 2013 201<br />

If we now iterate the SDe cleverly for the first two of these four diagrams, we<br />

obtain<br />

= +<br />

−<br />

−<br />

+ −<br />

since we do have<br />

= 0 , (7.107)<br />

= , (7.108)<br />

owing to the simple, momentum-independent structure of the seagull vertex.<br />

Comparing the lines of the proof for sQED with that of regular QED, the general<br />

proof strategy becomes clear : if in a diagram a slashed propagator occurs as<br />

one of the indicated lines of a (semi-)connected graph, we must iterate de SDe<br />

for that line, and then we can collect the various canceling contributions.<br />

7.4.3 The Gordon decomposition<br />

Consider a charged Dirac particle that scatters by emitting (or absorbing) a<br />

single photon. The corresponding current reads<br />

J µ = iQ¯h u(q) γµ u(p) , (7.109)<br />

where p is the incoming, and q the outgoing momentum. By the properties of<br />

the Dirac spinors we can write this as<br />

Now,<br />

J µ =<br />

iQ<br />

2m¯h u(q) ( /qγ µ + γ µ /p ) u(p) . (7.110)<br />

/qγ µ = q µ + 1 2 q α[γ α , γ µ ] = q µ − iq α σ αµ ,<br />

γ µ /p = p µ + 1 2 p α[γ µ , γ α ] = p µ + ip α σ αµ , (7.111)<br />

and the current takes the form<br />

J µ =<br />

iQ<br />

2m¯h u(q) ( (p + q) µ + i(p − q) α σ αµ) u(p) . (7.112)<br />

This is called the Gordon decomposition : the vertex is split up into a piece that<br />

we recognize as the sQED vertex, which is called the convection term, and a<br />

tensorial part, called the spin term. Both terms vanish individually under the<br />

handlebar operation.

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