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226 November 7, 2013<br />

If we were allowed to consider only the first of the two terms of the result (9.28),<br />

we could obtain the desired cancellation :<br />

⎥<br />

3∑ ⎥⎥⎦<br />

M j = 0 ⇒ Q W = Q D − Q U : (9.29)<br />

ɛ→k 1<br />

j=1<br />

but the second term in Eq.(9.28) spoils this idea by having a quite different<br />

algebraic structure ; no tuning of coupling constants is going to ensure that a<br />

W W γ vertex of the form (9.2.3) can do the job.<br />

Yang-Mills coupling<br />

Treating the W W γ vertex as a prettified sQED vertex does not work. It means<br />

that the photon-W interactions cannot be obtained by the minimal-substitution<br />

rule. This should not come as a surprize since the vertex (9.2.3) is only designed<br />

for graceful behaviour towards longitudinal photons, not towards longitudinal<br />

W ’s. We therefore propose to replace Eq.(9.2.3) by a vertex of the form<br />

i Q W<br />

¯h<br />

(<br />

(a1 p 1 + a 2 p 2 ) ρ g µν + (a 3 p 2 + a 4 p 3 ) µ g νρ + (a 5 p 3 + a 6 p 1 ) ν g ρµ) . (9.30)<br />

Note that because of momentum conservation each of the three terms need<br />

contain only two of the momenta; the constants a 1,...,6 are to be determined.<br />

This we shall do by considering several situations.<br />

First, we condier the process of decay of a photon in a W + W − pair :<br />

γ ∗ (q) → W + (k + , ɛ + ) W − (k − , ɛ − ) .<br />

Kinematically this is only possible if the photon is quite off-shell, and therefore<br />

we do not give it a polarization vector but leave its Lorentz index µ free. The<br />

matrix element is given by<br />

M = i¯h 1/2 Q W A µ ,<br />

A µ = (a 1 k + + a 2 k − ) µ (ɛ + · ɛ − )<br />

+((a 3 k − − a 4 q) · ɛ + )ɛ − µ + ((−a 5 q + a 6 k + ) · ɛ − )ɛ +<br />

µ<br />

= (a 1 k + + a 2 k − ) µ (ɛ + · ɛ − )<br />

+(a 3 − a 4 )(q · ɛ + )ɛ − µ + +(a 6 − a 5 )(q · ɛ − )ɛ + µ , (9.31)<br />

where in the last line we have used q = k + + k − and (k ± · ɛ ± ) = 0. Since even<br />

for off-shell photons the current must be strictly conserved we require that<br />

A µ q µ = 1 2 q2 (a 1 + a 2 )(ɛ + · ɛ − ) + (a 3 − a 4 − a 5 + a 6 )(q · ɛ + )(q · ɛ − ) = 0, (9.32)<br />

which leads to the following relations between the six constants :<br />

a 1 + a 2 = 0 , a 3 − a 4 = a 5 − a 6 . (9.33)

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