09.01.2014 Views

Pictures Paths Particles Processes

Pictures Paths Particles Processes

Pictures Paths Particles Processes

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

142 November 7, 2013<br />

under Lorentz transformations. It is somewhat surprising to see that the form of<br />

the Lorentz transformation in Clifford space is quite simple. Since all spinorial<br />

dyads ξη are Clifford elements, we find from the above that the transformation<br />

rules are<br />

ξ → Σ ξ , ξ → ξ Σ . (5.87)<br />

Let us now select the spinor of a particle in its rest frame, and consider rotations<br />

of the space axes. By x µ , y µ and z µ we shall mean the four-dimensional<br />

extensions of the spatial unit vectors in the x-, y- and z-directions, respectively.<br />

A rotation Σ z over an infintesimal angle θ from x towards y around the z axis 25<br />

is then determined by choosing<br />

p µ = x µ , q µ = cos(θ)x µ + sin(θ)y µ ≈ x µ + θy µ , (5.88)<br />

if we restrict ourselves to first order in θ. To this order, we find that |C| = 1/2,<br />

and so<br />

Σ z ≈ 1 2 (1 − (/x + θ/y)/x) = 1 + θ /x/y . (5.89)<br />

2<br />

(realize that x 2 = y 2 = z 2 = −1). The generators of the rotation group must<br />

therefore be 26 T x = β/y/z , T y = β/z/x , T z = β/x/y , (5.90)<br />

where we have used cyclicity, but not specified the constant β. This constant<br />

can be determined from the rotation group algebra requirement:<br />

which for the Dirac system is seen to read<br />

[T x , T y ] = T x T y − T y T x = i¯hT z , (5.91)<br />

[T x , T y ] = β 2 ( /y/z/z/x − /z/x/y/z ) = 2β 2 /x/y = 2β T z , (5.92)<br />

from which we see that β = i¯h/2. Noticing also that 27<br />

T z 2 = β 2 /x/y/x/y = −β 2 x 2 y 2 = ¯h2<br />

4 = T x 2 = T y 2 , (5.93)<br />

we conclude that the total-spin operator comes to<br />

⃗T 2 = T x 2 + T y 2 + T z 2 = 3 4¯h2 . (5.94)<br />

The spinors are, therefore, representatives of a spin-1/2 system.<br />

25 Here the confusing active-passive distinction rears its ugly head. We shall not worry about<br />

it since the rotation algebra is the same in each case.<br />

26 By inserting the Pauli representation of the Dirac matrices, one may figure out that these<br />

generators are nothing but the Pauli matrices in disguise. The present treatment aims at a<br />

more relativistic description.<br />

27 The fact that the square of any of the generators is proportional to the unit matrix is<br />

more or less a coincidence ; for systems with higher spins it no longer holds.

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!