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Automating Manufacturing Systems - Process Control and ...

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discrete actuators - 5.11<br />

1 NC limit switch<br />

1 indicator light<br />

a doubly acting pneumatic cylinder<br />

5.11 PRACTICE PROBLEM SOLUTIONS<br />

1. A = pi*r^2 = 3.14159in^2, P=FS*(F/A)=1.3(120/3.14159)=49.7psi. Note, if the cylinder were<br />

retracting we would need to subtract the rod area from the piston area. Note: this air pressure is<br />

much higher than normally found in a shop, so it would not be practical, <strong>and</strong> a redesign would<br />

be needed.<br />

2.<br />

cylinder<br />

V<br />

00<br />

S1<br />

+<br />

-<br />

24Vdc<br />

01<br />

02<br />

03<br />

S1<br />

sump<br />

pressure<br />

regulator<br />

release<br />

pump<br />

www.PA<strong>Control</strong>.com

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