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Automating Manufacturing Systems - Process Control and ...

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continuous actuators - 24.26<br />

24.7 PRACTICE PROBLEM SOLUTIONS<br />

1.<br />

a) P = 0.125⎛------<br />

in ⎞ R = 0.025---------<br />

in<br />

⎝rot⎠<br />

step<br />

0.025---------<br />

in<br />

θ =<br />

R<br />

-- = --------------------------<br />

step<br />

P<br />

0.125⎛<br />

⎝<br />

------<br />

in<br />

= 0.2---------<br />

rot Thus<br />

⎞ step<br />

rot⎠<br />

b) θ = 0.2--------- rot = 72 ---------<br />

deg<br />

step step<br />

------------------<br />

1<br />

0.2---------<br />

rot = 5 step ---------<br />

rot<br />

step<br />

c)<br />

PPS<br />

3 in ----<br />

= ------------------------<br />

s<br />

0.025---------<br />

in = 120 steps ------------<br />

s<br />

step<br />

2.<br />

a)<br />

pulses<br />

= ( 3rot) ⎛5 step --------- ⎞ = 15steps<br />

⎝ rot ⎠<br />

b) pulses<br />

--------------- = ⎛25 --------<br />

rot ⎞⎛ 5<br />

step<br />

--------- ⎞ = 125 steps ------------ = 125⎛------------<br />

1min ⎞steps<br />

------------ = 2.08 step ---------<br />

s ⎝ min⎠⎝<br />

rot ⎠ min ⎝ 60s ⎠ min s<br />

3.<br />

4.<br />

stepper motor<br />

vfd<br />

dc motor<br />

speed<br />

very low speeds<br />

limited speed range<br />

wide range<br />

torque<br />

low torque<br />

good at rated speed<br />

decreases at higher speeds<br />

www.PA<strong>Control</strong>.com

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