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8.3. A REPARAMETERIZATION OF THE MODEL REDUCTION PROBLEM 141<br />

Remark 8.3. Note that in the MIMO case, the corresponding H 2 -inner product is<br />

obtained by applying the trace opera<strong>to</strong>r <strong>to</strong> the expressions given above for the SISO<br />

case. The state-space formulation needs <strong>to</strong> be adapted in a similar fashion, by including<br />

the trace opera<strong>to</strong>r.<br />

8.3 A reparameterization of the H 2 model-order reduction problem<br />

From an algebraic point of view, note that the squared H 2 -norm of H(s) − G(s) in<br />

(8.13) can be worked out <strong>to</strong> constitute a (rather complicated) rational expression in<br />

terms of the 2n coefficients of a(s) and b(s), when<br />

G(s) = b(s)<br />

a(s) . (8.15)<br />

In Section 8.4 of this chapter we show how this criterion can be evaluated at some<br />

special points of interest by means of a third order homogeneous polynomial.<br />

From a geometric point of view it is appropriate <strong>to</strong> regard the problem of minimizing<br />

the criterion function in (8.13) as a projection problem within the Hardy space<br />

H 2 (Π + ) of functions that are analytic on the open right-half plane Π + and which<br />

satisfy the property that their H 2 -norm attains a well-defined finite value.<br />

Proceeding as in [50], it is well known that the space S n constitutes a smooth<br />

submanifold of H 2 (Π + ). Therefore, if b(s)/a(s) is an optimal approximation in S n <strong>to</strong><br />

e(s)/d(s) with respect <strong>to</strong> the H 2 -norm, then b(s)/a(s) is an orthogonal projection of<br />

e(s)/d(s) on<strong>to</strong>S n . The difference<br />

e(s)<br />

d(s) − b(s)<br />

a(s)<br />

(8.16)<br />

is perpendicular <strong>to</strong> the tangent space <strong>to</strong> S n at the point G(s). The tangent space <strong>to</strong> S n<br />

at G(s) is easily computed as the set {t(s)/a(s) 2 | t(s) polynomial of degree ≤ 2n−1}.<br />

Now, from the theory of Hardy spaces it is known that the orthogonal complement of<br />

this tangent space in H 2 (Π + ) is obtained as the set {a(−s) 2 R(s) | R(s) ∈H 2 (Π + )}.<br />

Consequently, G(s) is a stationary point if and only if there exists a function R(s) ∈<br />

H 2 (Π + ) for which:<br />

e(s)<br />

d(s) − b(s)<br />

a(s) = a(−s)2 R(s) (8.17)<br />

(see [8], [9], and [80]).<br />

Clearly R(s) needs <strong>to</strong> be a real and rational function and its poles are in the open<br />

left-half plane Π − . Since the fac<strong>to</strong>r a(−s) 2 has its zeros in the open right-half plane<br />

Π + none of its fac<strong>to</strong>rs cancel and it follows upon multiplication by a(s)d(s) that there<br />

exists a non-vanishing real polynomial q(s) =a(s)d(s)R(s) such that:<br />

e(s)a(s) − b(s)d(s) =a(−s) 2 q(s). (8.18)<br />

Note that q(s) 0 since H(s) and G(s) have different degrees. Note also that<br />

the degree of q(s) is≤ k − 1. The value k = N − n ≥ 1 is the co-order of the<br />

approximation G(s).

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