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250 APPENDIX A. LINEARIZING A 2-PARAMETER EIGENVALUE PROBLEM<br />

which is written as:<br />

)<br />

(P 0 + µP 1 + λP 2 w = 0<br />

(A.15)<br />

which is <strong>to</strong> be enhanced by suitable block rows <strong>to</strong> fix the particular structure of the<br />

eigenvec<strong>to</strong>r w. To achieve this goal, various ways exist. Now the problem is linear in<br />

both µ and λ and the dimensions of the matrices P 0 , P 1 , and P 2 are (m 2 n) × (m 2 n).<br />

Note that the eigenvec<strong>to</strong>r w is highly structured, since the vec<strong>to</strong>rs from which it is<br />

constructed, the vec<strong>to</strong>rs z, are structured <strong>to</strong>o: w =(z T ,λz T ,λ 2 z T ,...,λ m−1 z T ) T<br />

where z =(v T ,µv T ,µ 2 v T ,...,µ m−1 v T ) T .<br />

The eigenvalues of the original problem (A.1) can be found among the eigenvalues<br />

of (A.15) because the eigenvalue spectrum is unchanged. Moreover, the possible<br />

multiplicities among the eigenvalues in (A.1) are preserved when linearizing the polynomial<br />

problem. The eigenvec<strong>to</strong>rs of (A.1) can be recovered from the eigenvec<strong>to</strong>rs of<br />

(A.15) by making use of the internal structure of the eigenvec<strong>to</strong>rs w.<br />

Remark A.1. Note that the matrix M(µ, λ) in (A.1) does not necessarily has <strong>to</strong><br />

be square. Suppose that this matrix M is not square but rectangular. Then the<br />

linearization technique of this section can still be applied if the dimensions of the<br />

block matrices I and 0 are adapted conformably.<br />

A.3 Example<br />

Suppose a two-parameter eigenvalue problem is given involving a n × n matrix M<br />

polynomial in µ and λ. The <strong>to</strong>tal degree of the entries in the parameters µ and λ in<br />

the matrix M is three: m = 3. We can write the matrix M(µ, λ) as:<br />

M(µ, λ) =N 0 + µN 1 + λN 2 + µ 2 N 3 + µλN 5 +<br />

λ 2 N 4 + µ 3 N 6 + λ 2 µN 7 + λµ 2 N 8 + λ 3 N 9 .<br />

Using this, the polynomial matrix M(µ, λ) can be written as:<br />

M(µ, λ) =<br />

(<br />

(N 0 + λN 2 + λ 2 N 4 + λ 3 N 9 )+<br />

µ (N 1 + λN 5 + λ 2 N 7 )+<br />

µ 2 (N 3 + λN<br />

) 8 )+<br />

µ 3 (N 6 ) .<br />

(A.16)<br />

(A.17)<br />

When the matrices (N 0 + λN 2 + λ 2 N 4 + λ 3 N 9 ), (N 1 + λN 5 + λ 2 N 7 ), (N 3 + λN 8 )<br />

and (N 6 ) are denoted by the matrices M 0 (λ),M 1 (λ),M 2 (λ),M 3 (λ), respectively, the<br />

following formulation is equivalent:<br />

M(µ, λ) =M 0 (λ)+µM 1 (λ)+µ 2 M 2 (λ)+µ 3 M 3 (λ).<br />

(A.18)

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