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Control and Design of Microgrid Components - Power Systems ...

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o<br />

δ max = 15<br />

Figure 4.7 P <strong>and</strong> Q Plane Capability with Constant Voltage <strong>and</strong> Impedance.<br />

Figure 4.7 plots P <strong>and</strong> Q from the formulas inside Figure 4.5 assuming that<br />

δ<br />

p<br />

= δp max<br />

= 15 degrees <strong>and</strong> E=1pu. Then, the values for V ∈[ 06 ., 12 .]<br />

pu <strong>and</strong> X ∈ [ 0.1,1.0]pu<br />

are separately spanned. The result <strong>of</strong> overlapping the plots yields a map: positive values for Q<br />

imply capacitive power while negative values imply inductive injection. Assuming as an<br />

example a power factor <strong>of</strong> 0.8 it is possible to calculate Qmax as 0.75 pu when P=Pmax is 1.0<br />

pu. This means that there is a region between P=[0, 1.0] pu <strong>and</strong> Q=[-0.75, 0.75] pu that is<br />

identified in Figure 4.7 as a rectangle. This rectangle is just a simplification <strong>of</strong> the shape <strong>of</strong> the<br />

region describing the capability <strong>of</strong> the inverter to inject active <strong>and</strong> reactive power. The<br />

impedance must be such that the points inside this region are reachable. A value <strong>of</strong> the<br />

impedance around 0.2 pu would fulfill the requirement, but if one chooses a larger impedance<br />

some <strong>of</strong> the values inside the rectangle would not be reachable.<br />

Each value <strong>of</strong> the inductance defines a certain region in the space that can be reached: Figure 4.8<br />

shows this region for X=0.2 pu while δ is spanning from 0 o to 30 o . Figure 4.8 shows that with<br />

the inductor <strong>of</strong> size X=0.2 pu it is possible to reach the coordinate P=1.0 pu <strong>and</strong> Q=0.75 pu with<br />

an inverter voltage <strong>of</strong> about 1.12 pu <strong>and</strong> a power angle <strong>of</strong> 10 degrees.<br />

56

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