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Introductory Physics Volume Two

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5.4 More Examples 109<br />

Use the Biot-Savart law:<br />

⃗B = µ ∫<br />

0I<br />

4π<br />

= µ 0I<br />

4π<br />

∫2π<br />

0<br />

⃗ drs<br />

dt × [⃗r f − ⃗r s ]<br />

| ⃗r f − ⃗r s | 3 dt<br />

az cos tî + az sin tĵ + a 2ˆk dt<br />

(a 2 + z 2 ) 3 2<br />

Since the integrals of the cosine and sine vanish for the interval [0, 2π],<br />

the resulting magnetic field is:<br />

µ 0 Ia<br />

⃗B 2 ∫2π<br />

=<br />

ˆk dt<br />

4π (a 2 + z 2 ) 3 2<br />

−→<br />

⃗ B = µ 0I<br />

2<br />

0<br />

a 2<br />

(a 2 + z 2 ) 3 2<br />

ˆk<br />

Example<br />

A semi-circular shaped wire with radius a carryies a current I. What<br />

is the magnetic field caused at the center of the semi-circle’s diameter?<br />

B = ?<br />

a<br />

Divide the wire into small sections and compute the magentic field<br />

contribution due to one small section:<br />

I<br />

dθ<br />

dB<br />

dl<br />

The direction for all sections is up, by the right hand rule. Use the<br />

Biot-Savart law for the magnitude:<br />

d ⃗ B = µ 0<br />

4π<br />

= Iµ 0<br />

4π<br />

Id ⃗ l × ⃗r ′<br />

ˆk<br />

r ′ 3<br />

(dl)(a)<br />

ˆk,<br />

a 3

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