Introductory Physics Volume Two
Introductory Physics Volume Two
Introductory Physics Volume Two
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82 Magnetic Fields 4.2<br />
We can determine the dimensions of the magnetic<br />
field from the force equation:<br />
F = qvB −→ B = F qv<br />
The unit of magnetic field is the Tesla, abbreviated as<br />
just T.<br />
Newton<br />
Tesla =<br />
Coulomb · meter/second = Kilogram<br />
Coulomb · second<br />
§ 4.2 Magnetic Force on a Current<br />
If a current carrying wire is placed in a magnetic field it will experience<br />
a magnetic force. The current in the wire is composed of many<br />
moving charges. Each of these charges experiences a magnetic force.<br />
The force on the wire is the sum of the forces on all the moving charges<br />
in the wire.<br />
Theorem: Magnetic Force on a Current<br />
Suppose that you have a wire that is carrying a current I. A small<br />
section of wire of length ⃗ dl, where the vector points in the direction<br />
of the current, will experience a force<br />
⃗ dF = I ⃗ dl × ⃗ B<br />
The force on a longer section of wire can be found by integrating<br />
over the length of the section.<br />
∫<br />
⃗F = I dl ⃗ × B ⃗<br />
If the magnetic field is uniform over the region containing the wire<br />
then the following result can be proved.<br />
Theorem: Force on a Current in a Uniform Field<br />
Let ⃗ ∆l be a vector that points from the beginning to the end of a<br />
section of wire carrying a current I. If that section is in a uniform<br />
magnetic field, the force on that section is<br />
⃗F = I ⃗ ∆l × ⃗ B<br />
⊲ Problem 4.1<br />
Consider a semicircular piece of wire or radius R in the first two quadrants<br />
of the x-y plane. The wire carries of current I in the counterclockwise<br />
direction.