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Introductory Physics Volume Two

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82 Magnetic Fields 4.2<br />

We can determine the dimensions of the magnetic<br />

field from the force equation:<br />

F = qvB −→ B = F qv<br />

The unit of magnetic field is the Tesla, abbreviated as<br />

just T.<br />

Newton<br />

Tesla =<br />

Coulomb · meter/second = Kilogram<br />

Coulomb · second<br />

§ 4.2 Magnetic Force on a Current<br />

If a current carrying wire is placed in a magnetic field it will experience<br />

a magnetic force. The current in the wire is composed of many<br />

moving charges. Each of these charges experiences a magnetic force.<br />

The force on the wire is the sum of the forces on all the moving charges<br />

in the wire.<br />

Theorem: Magnetic Force on a Current<br />

Suppose that you have a wire that is carrying a current I. A small<br />

section of wire of length ⃗ dl, where the vector points in the direction<br />

of the current, will experience a force<br />

⃗ dF = I ⃗ dl × ⃗ B<br />

The force on a longer section of wire can be found by integrating<br />

over the length of the section.<br />

∫<br />

⃗F = I dl ⃗ × B ⃗<br />

If the magnetic field is uniform over the region containing the wire<br />

then the following result can be proved.<br />

Theorem: Force on a Current in a Uniform Field<br />

Let ⃗ ∆l be a vector that points from the beginning to the end of a<br />

section of wire carrying a current I. If that section is in a uniform<br />

magnetic field, the force on that section is<br />

⃗F = I ⃗ ∆l × ⃗ B<br />

⊲ Problem 4.1<br />

Consider a semicircular piece of wire or radius R in the first two quadrants<br />

of the x-y plane. The wire carries of current I in the counterclockwise<br />

direction.

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