12.11.2014 Views

Introductory Physics Volume Two

Introductory Physics Volume Two

Introductory Physics Volume Two

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

8.7 Virtual Image in a Converging Lens 169<br />

⊲ Problem 8.2<br />

Using geometric arguments, prove the thin lens equations.<br />

⊲ Problem 8.3<br />

You have a lens with a focal length of 100cm. You place an object at<br />

150cm from the lens. The object is 3cm tall.<br />

(a) Construct the image location using the principle rays.<br />

(b) Find the location of the image using the thin lens equation.<br />

(c) Find the height of the image from the magnification equation.<br />

§ 8.7 Virtual Image in a Converging Lens<br />

You do not get a real image for all positions of the object. When<br />

the object distance is smaller than the focal length, you get a virtual<br />

image. You have probably notice this effect before while using a magnifying<br />

glass: if you look at something far away through a magnifying<br />

glass, you will se the object upside down. If you move closer to the<br />

object at some point it flips over and appears right side up.<br />

Virtual Image<br />

Real Image<br />

image<br />

paper<br />

lens<br />

paper<br />

lens<br />

image<br />

In the photograph above you can notice a few things. In the photo on<br />

the left, the letters on the page are almost in-focus, this means that<br />

the image is not too far from the page. In contrast, in the photo on the<br />

right, the letters on the page are very out of focus, this tells us that<br />

the image is far from the page. This is verified by the ray diagrams.<br />

Here is a larger diagram, showing the construction of the virtual<br />

image, that corresponds to the photo on the left.

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!