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Introductory Physics Volume Two

Introductory Physics Volume Two

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20 Electric Field 1.6<br />

Definition: Electric Flux<br />

The electric flux (φ e ) through a surface is<br />

φ e = ⃗ E · ⃗A<br />

if the field is uniform over the surface. If the field is not uniform<br />

then one must integrate over the surface,<br />

∫<br />

φ e = ⃗E · dA ⃗<br />

We see that the dot product represents the dependence of the flux<br />

on the relative orientation of the surface and the field. When thinking<br />

of the flux integral over a surface it can be helpful to imagine gluing<br />

tacks to the surface with the nail part sticking out, so that you end up<br />

with a spiky covering of the surface. Each tack represents one small<br />

surface element dA ⃗ and the integral is the sum of the flux’s through all<br />

of the small surface element.<br />

Now we can state the theorem that relates the electric field to the<br />

charge density.<br />

Theorem: Gauss’s Law<br />

The electric flux out of any closed surface is proportional to the<br />

total charge enclosed within the surface.<br />

∮<br />

⃗E · dA ⃗ = Q in<br />

ɛ 0<br />

Note that the integral of the electric field over the surface does<br />

not depend on the charge density outside the surface in any way. For<br />

example if there is no charge inside the surface then the integral must<br />

be zero.<br />

Example<br />

We can use Gauss’s law in order to find the electric field strength.<br />

Here is an example of how this can be done. The result of this example<br />

is also generally useful.

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