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Introductory Physics Volume Two

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86 Magnetic Fields 4.5<br />

(a) Show that if v = E/B that the particles will go straight through<br />

the region without deflection.<br />

(b) Show that if v > E/B and q > 0 then the particles will be deflected<br />

in the negative y direction.<br />

(c) Show that if v > E/B and q < 0 then the particles will be deflected<br />

in the positive y direction.<br />

(d) Show that if v < E/B and q > 0 then the particles will be deflected<br />

in the positive y direction.<br />

A device setup with crossed magnetic and electric fields as in the<br />

previous problem is called a velocity selector. Since it sorts out the<br />

particles based on their speeds, if you select out just the ones that<br />

go straight ahead, you have selected particles with a particular speed<br />

v = E/B. By adjusting the field strengths you can choose what velocity<br />

you would like to select.<br />

§ 4.5 Hall Effect<br />

Let us look with more detail at the flow of current in a wire that<br />

is in a magnetic field. Suppose that we have a rectangular conductor<br />

with a current I running through it.<br />

w<br />

h<br />

If we consider the charges in the wire we see that there will be a<br />

magnetic force on the particles that will tend to deflect them to one<br />

face of the conductor.<br />

I<br />

-<br />

I<br />

But this force will be acting on all the free charges, so they will all shift<br />

upward as they move through the conductor. Keeping in mind that<br />

the positive charge in the conductor does not move, we see that this<br />

shift of the (negative) free charges will build up a net negative charge<br />

on one face of the conductor and net positive charge on the opposing<br />

face.<br />

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