Introductory Physics Volume Two
Introductory Physics Volume Two
Introductory Physics Volume Two
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86 Magnetic Fields 4.5<br />
(a) Show that if v = E/B that the particles will go straight through<br />
the region without deflection.<br />
(b) Show that if v > E/B and q > 0 then the particles will be deflected<br />
in the negative y direction.<br />
(c) Show that if v > E/B and q < 0 then the particles will be deflected<br />
in the positive y direction.<br />
(d) Show that if v < E/B and q > 0 then the particles will be deflected<br />
in the positive y direction.<br />
A device setup with crossed magnetic and electric fields as in the<br />
previous problem is called a velocity selector. Since it sorts out the<br />
particles based on their speeds, if you select out just the ones that<br />
go straight ahead, you have selected particles with a particular speed<br />
v = E/B. By adjusting the field strengths you can choose what velocity<br />
you would like to select.<br />
§ 4.5 Hall Effect<br />
Let us look with more detail at the flow of current in a wire that<br />
is in a magnetic field. Suppose that we have a rectangular conductor<br />
with a current I running through it.<br />
w<br />
h<br />
If we consider the charges in the wire we see that there will be a<br />
magnetic force on the particles that will tend to deflect them to one<br />
face of the conductor.<br />
I<br />
-<br />
I<br />
But this force will be acting on all the free charges, so they will all shift<br />
upward as they move through the conductor. Keeping in mind that<br />
the positive charge in the conductor does not move, we see that this<br />
shift of the (negative) free charges will build up a net negative charge<br />
on one face of the conductor and net positive charge on the opposing<br />
face.<br />
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