12.11.2014 Views

Introductory Physics Volume Two

Introductory Physics Volume Two

Introductory Physics Volume Two

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

2.1 Electric Potential 39<br />

Example<br />

Suppose that an electron moved from a region where the electric potential<br />

is 150 volts to a region where the electric potential is 100 volts.<br />

There is only the electric field acting on the electron. What would be<br />

the change in the kinetic energy of the electron? We know that the<br />

potential energy and electric potential are related: ∆V = ∆U/q.<br />

so that<br />

∆K + ∆U = 0<br />

∆K = −∆U = −q∆V = −(−e)(100V − 150V) = −8.0 × 10 −18 J<br />

In this example we see that negatively charged particles slow down<br />

when they go from a region of high electric potential to a region of low<br />

electric potential. A positively charged particles would speed up.<br />

Example<br />

Now let’s try an example where the field is not uniform.<br />

⃗E = α [ y 2 î + 2xyĵ ]<br />

If we move from the origin to the point (a, b) what is the change in the<br />

electric potential. First we need to pick a path from the starting point<br />

to the ending point. A straight line will do. Let ⃗r(t) = x(t)î + y(t)ĵ =<br />

atî + btĵ, we see that as the parameter t is varied from 0 to 1, that<br />

the vector ⃗r(t) points along the path from the origin to the final point<br />

(a, b): that is ⃗r(t) is the trajectory of a particle following our path. This<br />

function is called a parameterization of the path. Now we can compute<br />

the line integral ∫ E ⃗ · dr ⃗ since we can now write<br />

⃗dr = d⃗r<br />

dt dt = [ dx<br />

dt î + dy<br />

dt ĵ<br />

]<br />

dt = [aî + bĵ] dt

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!