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Introductory Physics Volume Two

Introductory Physics Volume Two

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184 Hints A<br />

6.6 Use a phasor diagram to draw Kirchhoff’s loop rule, then find the<br />

frequency that minimizes the effective impedance of the RLC combination.<br />

6.8 Use Faraday’s law. Assume that the magnetic field decreases at<br />

a constant rate over the 20 ms that it goes from 1.6 T to zero, that is<br />

dB/dt = (−1.6T)/(20ms).<br />

6.10 Since the field strength decreases as you move further from the<br />

wire you will need to do an integral in order to compute the magnetic<br />

flux.<br />

6.11 Use Ampere’s Law.<br />

6.13 Consider that Q = ∫ Idt and I = V/R = E/R.<br />

7.2 Start from x = A cos φ.<br />

7.3 Take a look at the diagram of the oscillator that shows the phase<br />

angle at different points in the cycle. For the last part remember that<br />

v = dx/dt and consider the quantity v/x.<br />

7.4 Recall that the phase is φ = ωt + φ 0 so that ∆φ = ω∆t. Then<br />

consider by how much the phase must change in order for the oscillator<br />

to complete one cycle.<br />

7.8 First compute the phase difference. Remember that φ 1 = −kr 1<br />

and φ 2 = −kr 2 . Next use the addition of two waves theorem.<br />

7.9 The collection of points with the same ∆r will form a continuous<br />

line, just like the collection of points that are all 5cm from a single<br />

point makes a circle or radius 5 cm.<br />

7.10 Treat the two holes as two sources.<br />

7.11 The phase of each path is now −kr plus the reflection phase<br />

shift.<br />

7.12 Find the distance from the lower speaker to the point P as a<br />

function of the distance d.<br />

7.15 The path difference occurs in air.<br />

7.16 Use the far field approximation to find the path difference.<br />

7.18 Use the trig identities in the appendix.<br />

7.19 There is a path difference, d sin θ, on both sides of the screen.<br />

7.22 The air gap between the plates will be wedge shaped, because<br />

the thickness of the air gap increases as you move toward the wire,<br />

there will be an increasing phase difference between the two reflected<br />

beams. This leads to the fringes.<br />

7.24 As the slit gets narrower the angle of the first minima increases.<br />

There is a limit to the increase.

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