Introductory Physics Volume Two
Introductory Physics Volume Two
Introductory Physics Volume Two
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8.10 Multi-Lens Optical Systems 173<br />
Example<br />
§ 8.9 Sign Conventions and Coordinates System<br />
We have used the coordinates<br />
(x o , y o ) for the object and the coordinates<br />
(x i , y i ) for the image. The<br />
direction of positive y is the same<br />
for both coordinate systems. The<br />
direction of positive x was opposite.<br />
Light<br />
In<br />
A curved mirror is also a lens. The coordinate<br />
sign convention, stated as follows,<br />
covers both types of lenses.<br />
• The x-axis of the object coordinate system<br />
is in the opposite direction as the incoming<br />
light.<br />
• The x-axis of the image coordinate system<br />
is in the same direction as the outgoing light.<br />
y o<br />
y i<br />
Light<br />
x o<br />
x Out i<br />
Transmitting Lens<br />
Light<br />
In<br />
Light<br />
Out<br />
x o<br />
x i<br />
y o<br />
y i<br />
Reflecting Lens<br />
A concave mirror (as shown) is a converging lens, while a convex<br />
mirror is a diverging lens. The sign convention for focal lengths is the<br />
same for mirrors.<br />
§ 8.10 Multi-Lens Optical Systems<br />
Most optical systems are composed of more than one lens. We do<br />
not need more theory in order to work with a multi-lens system. The<br />
light passes from one lens to the next in sequence. In order to do a<br />
computation with a multi-lens system, we need only use the image of<br />
one lens as the object of the next lens.<br />
Suppose that you have a diverging lens, f = −12cm, followed by a<br />
converging lens, f ′ = 16cm. The lenses are 20 cm apart. You place an<br />
object that is 9cm tall at a distance of 24 cm from the diverging lens.<br />
We can construct the final image as follows.<br />
24 cm<br />
20 cm<br />
28 cm 37.3 cm<br />
Mirror<br />
Object 1<br />
8cm<br />
12cm<br />
Image 1<br />
Object 2<br />
12cm<br />
16cm<br />
Or we could compute the final image from the thin lens equation. Given<br />
f = −12cm and x o = 24cm we can compute<br />
1<br />
= 1 x i f − 1 1<br />
=<br />
x o −12cm − 1<br />
24cm = − 3<br />
24cm −→ x i = −8cm<br />
16cm<br />
Image 2