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Introductory Physics Volume Two

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8.10 Multi-Lens Optical Systems 173<br />

Example<br />

§ 8.9 Sign Conventions and Coordinates System<br />

We have used the coordinates<br />

(x o , y o ) for the object and the coordinates<br />

(x i , y i ) for the image. The<br />

direction of positive y is the same<br />

for both coordinate systems. The<br />

direction of positive x was opposite.<br />

Light<br />

In<br />

A curved mirror is also a lens. The coordinate<br />

sign convention, stated as follows,<br />

covers both types of lenses.<br />

• The x-axis of the object coordinate system<br />

is in the opposite direction as the incoming<br />

light.<br />

• The x-axis of the image coordinate system<br />

is in the same direction as the outgoing light.<br />

y o<br />

y i<br />

Light<br />

x o<br />

x Out i<br />

Transmitting Lens<br />

Light<br />

In<br />

Light<br />

Out<br />

x o<br />

x i<br />

y o<br />

y i<br />

Reflecting Lens<br />

A concave mirror (as shown) is a converging lens, while a convex<br />

mirror is a diverging lens. The sign convention for focal lengths is the<br />

same for mirrors.<br />

§ 8.10 Multi-Lens Optical Systems<br />

Most optical systems are composed of more than one lens. We do<br />

not need more theory in order to work with a multi-lens system. The<br />

light passes from one lens to the next in sequence. In order to do a<br />

computation with a multi-lens system, we need only use the image of<br />

one lens as the object of the next lens.<br />

Suppose that you have a diverging lens, f = −12cm, followed by a<br />

converging lens, f ′ = 16cm. The lenses are 20 cm apart. You place an<br />

object that is 9cm tall at a distance of 24 cm from the diverging lens.<br />

We can construct the final image as follows.<br />

24 cm<br />

20 cm<br />

28 cm 37.3 cm<br />

Mirror<br />

Object 1<br />

8cm<br />

12cm<br />

Image 1<br />

Object 2<br />

12cm<br />

16cm<br />

Or we could compute the final image from the thin lens equation. Given<br />

f = −12cm and x o = 24cm we can compute<br />

1<br />

= 1 x i f − 1 1<br />

=<br />

x o −12cm − 1<br />

24cm = − 3<br />

24cm −→ x i = −8cm<br />

16cm<br />

Image 2

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