12.11.2014 Views

Introductory Physics Volume Two

Introductory Physics Volume Two

Introductory Physics Volume Two

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

154 Wave Optics 7.10<br />

The reason that we care the wavelength has changed, is that when<br />

we use the result that ∆r = m λ 2<br />

we need to use the wavelength where<br />

the path difference ∆r occurs. In the case considered above, the extra<br />

bit of path occurs within the oil, so we need to use the wavelength in<br />

the oil.<br />

In order to understand the root cause of the second complication,<br />

consider a soap bubble again. If you make a soap bubble and watch it<br />

carefully, you will notice that just before it pops, it appears that the top<br />

of the bubble has a hole in it. There is not actually a hole, but the top<br />

of the bubble looks like it has a hole because when the bubble gets very<br />

thin, no light is reflected from the surface of the bubble. Let us consider<br />

what our prediction would be for a very thin bubble. From our work<br />

with the oil film we expect that we will get a maximum reflection when<br />

2t = mλ/2, and m is even. Recall also that m = 0 gives a maximum,<br />

so t ≈ 0 should give a maximum for all wavelengths. Thus we expect<br />

the soap bubble to reflect very well when the film of bubble juice gets<br />

very thin. The truth is just the opposite.<br />

The key to this puzzle is to understand that when a wave is reflected<br />

it can be inverted, that is the direction of the displacement can<br />

be reversed. But a reversal is the same as a π phase shift.<br />

Fact: Reflection Phase Shift<br />

When a wave is reflected at an interface between two media there<br />

will be a π phase shift in the reflected wave if the index of refraction<br />

of the incident medium is lower than the index of refraction of the<br />

reflecting medium. If the incident medium has a higher index,<br />

there is no phase shift.<br />

⊲ Problem 7.11<br />

Explain using the reflection phase shift why a thin soap bubble reflects<br />

no light.<br />

§ 7.10 Single Slit Diffraction<br />

If a wave is passed through a rectangular hole that is much narrower<br />

in one direction than the other we find that we get an interference<br />

pattern like we do with a two source. Such a hole is usually referred to<br />

as a slit since it is so narrow in one direction.

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!