Introductory Physics Volume Two
Introductory Physics Volume Two
Introductory Physics Volume Two
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110 Sources of Magnetic Field 5.4<br />
since d ⃗ l and the radius vector to the point are perpendicular. The<br />
length of dl can be approximated by the length of the arc subtended<br />
by the angle ∆θ, so<br />
|dB| ⃗ = Iµ 0 (adθ)(a)<br />
4π a 3 ,<br />
= Iµ 0 dθ<br />
4π a<br />
To find the magnetic field due to the entire wire, integrate:<br />
B = Iµ 0<br />
4π<br />
∫ π<br />
0<br />
dθ<br />
a = Iµ 0<br />
4a<br />
Example<br />
<strong>Two</strong> sections of straight wire carrying electric current lie parallel to<br />
each other, a distance b apart:<br />
I 2<br />
b<br />
a<br />
I 1<br />
The leftmost ends of the wires are aligned. What is the force that<br />
current I 1 exerts on current I 2 ? Draw a coordinate system:<br />
y<br />
dx'<br />
x'<br />
I 2<br />
b<br />
I 1<br />
x<br />
x=-<br />
a<br />
2<br />
The z-axis points out of the page. From a previous example, we know<br />
that the magnetic field due to I 1 in the xy-plane is<br />
⎛<br />
⎞<br />
⃗B 2 (x, y) = µ 0I 1 x +<br />
⎝<br />
a 2<br />
x − a 2<br />
√<br />
4πy (x )<br />
− √ ⎠ ˆk<br />
+<br />
a 2<br />
2 + y<br />
2 (x −<br />
a<br />
2 )2 + y 2