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Introductory Physics Volume Two

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6.4 Inductance 121<br />

Example<br />

Suppose that you have the circuit shown.<br />

By some means you have established a current<br />

in the circuit (perhaps it is an induced current<br />

caused by some external magnetic field) such<br />

+ ε –<br />

that at t = 0 the current is I 0 . At t = 0 the<br />

external cause of the current disappears. What<br />

will happen to the current? – ΔV +<br />

I<br />

Since the inductor opposes the change in the current the current<br />

will not stop abruptly. Instead it will decrease gradually, the inductor<br />

will drive the circuit for a while. Note that this implies that an inductor<br />

can store energy, much like a capacitor can. Let us see how we would<br />

do the circuit analysis of this system.<br />

Kirchhoff’s Loop rule give us that<br />

E + ∆V = 0<br />

−→ L dI<br />

dt + IR = 0<br />

−→ dI<br />

dt = −R L I<br />

−→ I(t) = I 0 e − R L t<br />

Thus we see that the current will decay exponentially.<br />

I<br />

⊲ Problem 6.3<br />

The circuit below is assembled with the switch open. At the time t = 0<br />

the switch is closed.<br />

+ ε –<br />

V S<br />

+<br />

–<br />

I<br />

– ΔV<br />

+<br />

(a) What is the current as a function of time?<br />

(b) What is the EMF as a function of time?<br />

(c) What is the voltage on the resistor as a function of time?<br />

(d) Check to see if Kirchhoff’s loop rule is satisfied at all times.<br />

I

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