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Introductory Physics Volume Two

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92 Magnetic Fields 4.6<br />

The net force is<br />

⃗F = îF 1 − ĵF 2<br />

= îIL 1 B − ĵIL 2 B<br />

So the direction is given by<br />

( ) ( )<br />

θ = tan −1 IL2 B<br />

= tan −1 L2<br />

,<br />

IL 1 B<br />

L 1<br />

where θ is below the x-axis. The magnitude of the force is<br />

√<br />

F =<br />

√F1 2 + F 2 2 = IB L 2 1 + L2 2<br />

Example<br />

What is the net force on an a × b rectangular loop of wire carrying a<br />

current I that is in a uniform magnetic field perpendicular to the loop’s<br />

plane?<br />

Assume a direction for the magnetic field and use the right hand rule<br />

to draw the forces on each segment of the loop:<br />

a<br />

F 1<br />

b<br />

F 2<br />

F 3<br />

F 4<br />

B<br />

The net force on the loop is:<br />

⃗F = ⃗ F 1 + ⃗ F 2 + ⃗ F 3 + ⃗ F 4<br />

= î(F 2 − F 4 ) + ĵ(F 3 − F 1 )<br />

= î(IbB − IbB) + ĵ(IaB − IaB)<br />

= 0<br />

I<br />

Example<br />

Show that the magnetic force due to a uniform magnetic field for any<br />

closed current loop is zero.<br />

The force law states<br />

∮<br />

⃗F = I d ⃗ l × B ⃗

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