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Woo Young Lee Lecture Notes on Operator Theory

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CHAPTER 4.<br />

WEIGHTED SHIFTS<br />

If ν is defined <strong>on</strong> [0, ||T || 2 ] by<br />

ν(∆) := µ ( {z : |z| 2 ∈ ∆} ) ,<br />

then ν is a probability measure and γ n = ∫ t n dν(t).<br />

(⇐) If ν is the measure satisfying (4.1), define the measure µ by dµ(re iθ ) =<br />

1<br />

2π dθdµ(r). Then we can see that T ∼ = S µ .<br />

Example 4.1.5. (a) The Bergman shift B α is the weighted shift with weight sequence<br />

α ≡ {α n } given by<br />

√<br />

n + 1<br />

α n = (n ≥ 0).<br />

n + 2<br />

Then B α is subnormal: indeed,<br />

γ n := α 2 0α 2 1 · · · α 2 n−1 = 1 2 · 2<br />

3 · · · n<br />

n + 1 = 1<br />

n + 1<br />

and if we define µ(t) = t, i.e., dµ = dt then<br />

∫ 1<br />

0<br />

t n dµ(t) = 1<br />

n + 1 = γ n.<br />

(b) If α n : β, 1, 1, 1, · · · then W α is subnormal: indeed γ n = β 2 and if we define<br />

dµ = β 2 δ 1 + (1 − β 2 )δ 0 then ∫ 1<br />

0 tn dµ = β 2 = γ n .<br />

Remark. Recall that the Bergman space A(D) for D is defined by<br />

{<br />

∫<br />

}<br />

A(D) := f : D → C : f is analytic with |f| 2 dµ < ∞ .<br />

Then the orth<strong>on</strong>ormal basis for A(D) is given by {e n ≡ √ n + 1 z n : n = 0, 1, 2, · · · }<br />

with dµ = 1 π<br />

dA. The Bergman operator T : A(D) → A(D) is defined by<br />

T f = zf.<br />

In this case the matrix (α ij ) of the Bergman operator T with respect to the basis<br />

{e n ≡ √ n + 1 z n : n = 0, 1, 2, · · · } is given by<br />

α ij = ⟨T e j , e i ⟩<br />

= ⟨T √ j + 1 z j , √ i + 1 z i ⟩<br />

= ⟨ √ j + 1 z j+1 , √ i + 1 z i ⟩<br />

= √ ∫<br />

(j + 1)(i + 1) z j+1 z i dµ<br />

D<br />

∫ 2π ∫ 1<br />

= √ (j + 1)(i + 1) 1 π 0<br />

{√<br />

j+1<br />

=<br />

j+2<br />

(i = j + 1)<br />

0 (i ≠ j + 1) :<br />

107<br />

0<br />

D<br />

r j+1+i e i(j+1−i)θ · rdr dθ

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