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Woo Young Lee Lecture Notes on Operator Theory

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CHAPTER 5.<br />

TOEPLITZ THEORY<br />

Theorem 5.1.16. If C is the commutator ideal in T (L ∞ ), then the mapping ξ c<br />

induced from L ∞ to T (L ∞ )/C by ξ is a ∗-isometrical isomorphism. Thus there is a<br />

short exact sequence<br />

Proof. See [Do1].<br />

0 −→ C −→ T (L ∞ ) −→ L ∞ −→ 0.<br />

The commutator ideal C c<strong>on</strong>tains compact operators.<br />

Propositi<strong>on</strong> 5.1.17. The commutator ideal in T (C(T)) = K(H 2 ). Hence the commutator<br />

ideal of T (L ∞ ) c<strong>on</strong>tains K(H 2 ).<br />

Proof. Since T z is the unilateral shift, we can see that the commutator ideal of<br />

T (C(T)) c<strong>on</strong>tains the rank <strong>on</strong>e operator Tz ∗ T z − T z Tz ∗ . Moreover, T (C(T)) is irreducible<br />

since T z has no proper reducing subspaces by Beurling’s theorem. Therefore<br />

T (C(T)) c<strong>on</strong>tains K(H 2 ). Since T z is normal modulo a compact operator and generates<br />

the algebra T (C(T)), it follows that T (C(T))/K(H 2 ) is commutative. Hence<br />

K(H 2 ) c<strong>on</strong>tains the commutator ideal of T (C(T)). But since K(H 2 ) is simple (i.e., it<br />

has no n<strong>on</strong>trivial closed ideal), we can c<strong>on</strong>clude that K(H 2 ) is the commutator ideal<br />

of T (C(T)).<br />

Corollary 5.1.18. There exists a ∗-homomorphism ζ : T (L ∞ )/K(H 2 ) −→ L ∞<br />

such that the following diagram commutes:<br />

T (L ∞ )<br />

❏ ❏❏❏❏❏❏❏❏<br />

ρ<br />

π<br />

ζ<br />

♣♣♣♣♣♣♣♣♣♣♣<br />

L ∞ (T)<br />

T (L ∞ )/K(H 2 )<br />

Corollary 5.1.19. Let φ ∈ L ∞ . If T φ is Fredholm then φ is invertible in L ∞ .<br />

Proof. If T φ is Fredholm then π(T φ ) is invertible in T (L ∞ )/K(H 2 ), so φ = ρ(T φ ) =<br />

(ζ ◦ π)(T φ ) is invertible in L ∞ .<br />

From Corollary 5.1.18, we have:<br />

(i) ||T φ || ≤ ||T φ + K|| for every compact operator K because ||T φ || = ||φ|| ∞ =<br />

||ζ(T φ + K)|| ≤ ||T φ + K||.<br />

(ii) The <strong>on</strong>ly compact Toeplitz operator is 0 because ||K|| ≤ ||K + K|| ⇒ K = 0.<br />

Propositi<strong>on</strong> 5.1.20. If φ is invertible in L ∞ such that R(φ) ⊆ the open right halfplane,<br />

then T φ is invertible.<br />

165

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