Woo Young Lee Lecture Notes on Operator Theory
Woo Young Lee Lecture Notes on Operator Theory
Woo Young Lee Lecture Notes on Operator Theory
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CHAPTER 4.<br />
WEIGHTED SHIFTS<br />
Therefore if W α is 2-hyp<strong>on</strong>ormal then by Lemma 4.4.7, the sequences<br />
{ α<br />
2<br />
n+1 − α 2 n<br />
α 2 n − α 2 n−1<br />
} ∞<br />
n=2<br />
and<br />
{ α<br />
2<br />
n−1 − α 2 n−2<br />
α 2 n − α 2 n−1<br />
} ∞<br />
n=2<br />
are both bounded, so that {k n } ∞ n=2 is bounded. This proves Claim 2.<br />
Write k := sup n k n . Without loss of generality we assume k < 1 (this is possible<br />
from the observati<strong>on</strong> that cα induces {c 2 k n }). Choose a sufficiently small perturbati<strong>on</strong><br />
α ′ of α such that if we let<br />
h :=<br />
sup<br />
0≤l≤N+2;0≤m≤1<br />
N+4<br />
∑<br />
∣<br />
k=4<br />
p ′ k−2<br />
⎛<br />
∏<br />
⎝<br />
N+3<br />
v j<br />
′<br />
j=k<br />
⎞<br />
⎠ c ′ (k − 3, l) + v N+3 ′ · · · v 3 ′ ρ ′ m<br />
∣<br />
(4.21)<br />
then<br />
c ′ (N + 3, i) − 1 h > 0 (0 ≤ i ≤ N + 3) (4.22)<br />
1 − k<br />
(this is always possible because by Theorem 4.4.2, we can choose a sufficiently small<br />
|p ′ i | such that<br />
c ′ (N + 3, i) > v 0 · · · v i−1 u i · · · u N+3 − ϵ and |h| < (1 − k) ( v 0 · · · v i−1 u i · · · u N+3 − ϵ )<br />
for any small ϵ > 0).<br />
Claim 3. For j ≥ 4 and 0 ≤ i ≤ N + j,<br />
)<br />
∑j−3<br />
c ′ (N + j, i) ≥ u N+j · · · u N+4<br />
(c ′ (N + 3, i) − k n h . (4.23)<br />
Proof of Claim 3. We use inducti<strong>on</strong>. If j = 4 then by Claim 1 and (4.21),<br />
c ′ (N + 4, i) = u ′ N+4c ′ (N + 3, i) + p ′ N+3c ′ (N + 2, i − 1)<br />
⎛ ⎞<br />
N+4<br />
∑<br />
N+3<br />
∏<br />
+ v N+4<br />
′ p ′ ⎝<br />
k−2 v j<br />
′ ⎠ c ′ (k − 3, i − N + k − 6) + v N+4 ′ · · · v 3ρ ′ ′ i−(N+3)<br />
k=4<br />
j=k<br />
n=1<br />
≥ u ′ N+4c ′ (N + 3, i) + p ′ N+3c ′ (N + 2, i − 1) − v ′ N+4h<br />
≥ u N+4<br />
(<br />
c ′ (N + 3, i) − k N+4 h )<br />
≥ u N+4<br />
(<br />
c ′ (N + 3, i) − k h )<br />
because u ′ N+4 = u N+4, v ′ N+4 = v N+4 and p ′ N+3 = p N+3 ≥ 0. Now suppose (4.23)<br />
131