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Woo Young Lee Lecture Notes on Operator Theory

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CHAPTER 3.<br />

HYPONORMAL AND SUBNORMAL THEORY<br />

We should prove that P k → 1(SOT). Since {P k } is increasing, L = cl ∪ k ranP k is a<br />

closed linear space. To show that P k → 1(SOT) it suffices to show that L = H. To<br />

do this, it suffices to show that f(T )L ⊆ L for all f ∈ Rat(σ(T )). Since {λ j } is dense<br />

in σ(T ) c , it is <strong>on</strong>ly necessary to show that f(T )L ⊆ L when f is a rati<strong>on</strong>al functi<strong>on</strong><br />

with poles in {λ j }. Hence we must show that<br />

T L ⊆ L and (T − λ j ) −1 L ⊆ L.<br />

From the definiti<strong>on</strong> of L we see that these two c<strong>on</strong>diti<strong>on</strong>s are equivalent, respectively,<br />

to show that for all β ≥ 1:<br />

)<br />

T<br />

(T j (T − λ 1 ) −1 · · · (T − λ k ) −1 g i ∈ L for 0 ≤ j ≤ 2k ; (3.1)<br />

(T − λ m ) −1 (<br />

T j (T − λ 1 ) −1 · · · (T − λ k ) −1 g i<br />

)<br />

∈ L for 0 ≤ j ≤ 2k and all m. (3.2)<br />

To prove (3.1) we need <strong>on</strong>ly c<strong>on</strong>sider the case where j = 2k. Now<br />

T 2k+1 (T − λ 1 ) −1 · · · (T − λ 2k ) −1 g i ∈ ranP 2k<br />

and A = (T − λ k+1 ) · · · (T − λ 2k ) is a polynomial in T of degree 2k − k. Hence<br />

T 2k+1 (T −λ 1 ) −1 · · · (T −λ k ) −1 g i = AT 2k+1 (T −λ 1 ) −1 · · · (T −λ 2k ) −1 g i ∈ ranP 2k ⊆ L,<br />

which proves (3.1).<br />

Since (3.1) implies that L is an invariant subspace for T , to show (3.2) it suffices<br />

to show that<br />

(<br />

)<br />

(T − λ m ) −1 (T − λ 1 ) −1 · · · (T − λ k ) −1 g i ∈ L for all m.<br />

Since λ m is repeated infinitely often, we may assume m ≥ k + 2. If B = (T −<br />

λ k+1 ) · · · (T − λ m−1 ), then B is a polynomial in T of degree m + k − 1. Hence<br />

(<br />

)<br />

(T −λ m ) −1 (T −λ 1 ) −1 · · · (T −λ k ) −1 g i = B(T −λ 1 ) −1 · · · (T −λ m ) −1 g i ∈ ranP m ⊆ L,<br />

which proves (3.2).<br />

Lemma 3.2.6. If T ∈ B(H) is an m-multicyclic hyp<strong>on</strong>ormal operator then<br />

tr [T ∗ , T ] ≤ m∥T ∥ 2 .<br />

Proof. By Lemma 3.2.5, there exists an increasing sequence {P k } of finite rank projecti<strong>on</strong>s<br />

such that P k ↑ 1(SOT) and rank [P ⊥ k T P k] ≤ m for all k ≥ 1. Note that<br />

∥P ⊥ k T P k ∥ 2 2 ≤ m∥P ⊥ k T P k ∥ 2 .<br />

83

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